我有两张桌子: -
manu_table
product_id, manufacturer
1, ford
2, ford
3, toyota
product_table
product_id, score
1, 80
2, 60
3, 40
我想在摘要表中为每个制造商存储得分最高的product_id: -
summary_table
manufacturer, max_score
ford, 1
toyota, 3
到目前为止,我已经: -
UPDATE summary_table st
SET max_score = (
SELECT product_id
FROM (
SELECT manufacturer, product_id, max(score) as ms
FROM manu_table
LEFT JOIN product_table USING (product_id)
group by product_id) t)
WHERE st.manufacturer = manu_table.manufacturer;
遇到麻烦......非常感谢所有帮助。
答案 0 :(得分:3)
尝试此查询 -
UPDATE summary_table st
JOIN (
SELECT mt.manufacturer, MAX(pt.score) max_score FROM manu_table mt
JOIN product_table pt
ON mt.product_id = pt.product_id
GROUP BY mt.manufacturer) t
ON t.manufacturer = st.manufacturer
SET st.max_score = t.max_score
此查询将product_id设置为最高得分:
UPDATE summary_table st
JOIN (SELECT t1.* FROM
(SELECT mt.*, pt.score FROM manu_table mt JOIN product_table pt ON mt.product_id = pt.product_id) t1
JOIN (
SELECT mt.manufacturer, MAX(pt.score) max_score FROM manu_table mt
JOIN product_table pt
ON mt.product_id = pt.product_id
GROUP BY mt.manufacturer
) t2
ON t1.manufacturer = t2.manufacturer AND t1.score = t2.max_score
) t
ON t.manufacturer = st.manufacturer
SET st.max_score = t.product_id
答案 1 :(得分:2)
我理解这个问题我认为这会有效,我使用MAX(Product_ID)
只是为了解决任何重复问题,其中同一制造商的2个产品可能具有相同的分数,并且都是最高分。您可能希望以不同方式解决重复项。
UPDATE summary_table
SET max_score =
( SELECT MAX(m.Product_ID) [MaxScoreProductID]
FROM manu_table m
INNER JOIN product_table p
ON m.Product_ID = p.Product_ID
INNER JOIN
( SELECT Manufacturer, MAX(Score) [MaxScore]
FROM manu_table m
LEFT JOIN product_table p
ON m.Product_ID = p.Product_ID
GROUP BY Manufacturer
) ms
ON ms.Manufacturer = m.Manufacturer
AND ms.MaxScore = p.Score
WHERE m.Manufacturer = summary_table.Manufacturer
GROUP BY m.Manufacturer
)