Question

所以我已经制作了这段代码来获取GPS位置，日期的值和时间。然后我会尝试用JSON制作它们并发送它们通过Wi-Fi到服务器。无论如何，问题是它总是读取以前的位置值。它始终从中读取值 “网络”部分由前面的值提供的JSON。该当前位置，打印只有两个括号“{}”，你可以看到你运行代码。

运行脚本时，手机上的GPS图标无法激活直接从手机。我想代码是自我解释但是如果有任何问题请问。

import android,time,datetime
droid = android.Android()

latitudine = "initial value"
longitudine = "initial value"
indexVal = 1
lostSignal = False

while True:
 print "~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~\nNew reading: #" + str(indexVal) +"\n"
 droid.startLocating()
 locatie = droid.readLocation().result
 droid.stopLocating()
 print "Reading result: " + str(locatie)
 if locatie == {}:
  print "Current location information not available"
 locatie=droid.getLastKnownLocation().result
 if locatie != {}:
  if locatie['gps'] == None:
   if locatie['network'] == {}:
    latitudine = str(locatie['passive']['latitude'])
    longitudine = str(locatie['passive']['longitude'])
    print "Reading passive data (from last known location):"
    print longitudine
    print latitudine
    lostSignal = True
   elif locatie['network'] != {}:
    latitudine = str(locatie['network']['latitude'])
    longitudine = str(locatie['network']['longitude'])
    print "Reading data from network:"
    print latitudine
    print longitudine
    lostSignal = True
  elif locatie['gps']!=None:
   if lostSignal == True:
    droid.vibrate(500)
    lostSignal = False
    latitudine=str(locatie['gps']['latitude'])
    longitudine=str(locatie['gps']['longitude'])
    print "Reading data from GPS:"
    print latitudine
    print longitudine
    droid.notify("GPS found","GPS signal found.\nData aquired")

 print "\nFull available information:\n"
 for locInfo in locatie.iteritems():
 print str(locInfo)
 print "\n"

 now = datetime.datetime.now()

 ora = now.hour
 minut = now.minute
 secunda = now.second

 ziua = now.day
 luna = now.month
 an = now.year

 print str(ora)+":"+str(minut)+":"+str(secunda)+" / "+str(ziua)+"-"+str(luna)+"-"+str(an)
 indexVal += 1
 time.sleep(20)

Answer 1

在调用readLocation之前调用eventWaitFor（“location”）。您可能还想使用eventPoll，eventClearBuffer或eventWait。

GPS传感器启动非常慢，因为它需要获取卫星，同步时间，然后根据卫星信号的定时对位置进行三角测量。此外，由于您在未指定更新频率的情况下调用了startLocating，因此您将获得默认频率60,000毫秒或每分钟一次。

在SL4a中使用Python读取GPS值不起作用

1 个答案: