提交后保留查询生成下拉框的值

Question

我使用查询结果填充了下拉框的选项。如何在用户提交后保留所选值？

以下是代码：

$query="SELECT trainingName,trainingID FROM training ORDER BY trainingName";

$result = mysql_query ($query);
echo "<select name='training' value=selected>Training Name</option>";
$training = strip_tags(@$_POST['training']);

echo "<option>---------------------Select---------------------</option>";
while($nt=mysql_fetch_array($result)){
echo "<option value=$nt[trainingID]>$nt[trainingName]</option>";
}

谢谢！

Answer 1

试试这个：

$query="SELECT trainingName,trainingID FROM training ORDER BY trainingName";

$result = mysql_query ($query);
echo "<select name='training'>";
echo "<option>---------------------Select---------------------</option>";
while($nt=mysql_fetch_array($result)){
   $selected = false;
   // check if the current value equals the value submited
   if($_POST['training'] == $nt['trainingID']){
       $selected = true;
   }

   // show selected attribute only if $selected is true
   echo "<option value='{$nt['trainingID']}' ". ($selected ? "selected" : "") .">{$nt['trainingName']}</option>";
}
echo '</select>';