这是一个将列表提交到房地产列表数据库的简单表格。这是我第一次这样做,所以如果你发现任何我正在做的事情,这是不好的做法,或者只是愚蠢,请告诉我。
无论如何,关于我得到的错误:
Parse error: syntax error, unexpected T_IF, expecting ',' or ';' in C:\Program Files\EasyPHP-5.3.9\www\addform.php on line 62
我没有看到任何缺少分号的行,第62行是if语句....这个错误是什么?
<?php
//set database login variables
require_once 'login.php';
//connect to server
$db_server = mysql_connect($db_hostname, $db_username, $db_password);
//all server access lines have to be dealt with better than this. See page 227. Probably create a function.
//Note to self: look into try/catch in php
if (!$db_server) die("Unable to connect to database: " . msql_error());
mysql_select_db($db_database, $db_server) or die('Unable to select database: ' . mysql_error());
$submitted = false;
//Checking if values were passed
if (isset($_POST['area']) &&
isset($_POST['type']) &&
isset($_POST['price']) &&
isset($_POST['bedrooms']) &&
isset($_POST['fullbath']) &&
isset($_POST['halfbath']) &&
isset($_POST['sqft']))
//if passed, set variables accordingly
{
$area = get_post('area');
$type = get_post('type');
$price = get_post('price');
$bedrooms = get_post('bedrooms');
$fullbath = get_post('fullbath');
$halfbath = get_post('halfbath');
$sqft = get_post('sqft');
$submitted = true;
}
//optional field
if (isset($_POST['remarks']))
{
$remarks = get_post('remarks');
}
else
{$remarks = '';}
//form HTML
echo <<<_END
<form action="addform.php" method="post">
Area: <select name="area" size="1">
<option value="Hoboken">Hoboken</options>
<option value="Jersey City">Jersey City</options>
<option value="Weehawken">Weehawken</options>
</select><br />
Type: <select name="type" size="1">
<option value="rent">Rental</options>
<option value="sale">Sale</options>
<option value="commercial">Commercial</option>
</select><br />
Price: <input type="text" name="price" /><br />
Bedrooms: <input type="text" name="bedrooms" /><br />
Full Bathrooms: <input type="text" name="fullbath" /><br />
Half Bathrooms: <input type="text" name="halfbath" /><br />
Square Feet: <input type="text" name="sqft" /><br />
Remarks: <textarea name="remarks" wrap="soft" /><br />
<input type="submit" value="Add Listing" />
</form>
<br />
<br />
_END
//if data was provided, insert it into database and confirm
if ($submitted) {
$query = "INSET INTO bix (area, type, price, bedrooms, fullbath, halfbath, sqft, remarks) VALUES('$area', '$type', '$price', $bedrooms', '$fullbath', '$halfbath', '$sqft', '$remarks')";
if (mysql_query($query)){
echo "listing inserted.<br /></br />";
} else {
echo "insert fail: $query <br /><br />";
}
}
答案 0 :(得分:4)
您在echo
此处_END
答案 1 :(得分:3)
您在;
声明之前肯定错过了if
。第61行?
答案 2 :(得分:0)
好吧,你的$ query确实存在问题。
$query = "INSET INTO bix (area, type, price, bedrooms, fullbath, halfbath, sqft, remarks) VALUES('$area', '$type', '$price', $bedrooms', '$fullbath', '$halfbath', '$sqft', '$remarks')";
INSET
可能应为INSERT
,您希望'$bedrooms'
代替$bedrooms'
除此之外,您在结束_END