我有一个EditText
字段,上面有一个Customer Text Watcher。在一段代码中,我需要使用.setText("whatever")
更改EditText中的值。
问题是,一旦我进行了更改,调用的afterTextChanged
方法就会创建一个无限循环。如何在不触发afterTextChanged的情况下更改文本?
我需要afterTextChanged方法中的文字,所以不建议删除TextWatcher
。
答案 0 :(得分:80)
您可以查看当前具有焦点的视图,以区分用户和程序触发的事件。
EditText myEditText = (EditText) findViewById(R.id.myEditText);
myEditText.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if (getCurrentFocus() == myEditText) {
// is only executed if the EditText was directly changed by the user
}
}
//...
});
修改:正确提及LairdPleng,如果myEditText
已经具有焦点且您以编程方式更改文本,则此功能无效。因此,在致电myEditText.setText(...)
之前,您应该将myEditText.clearFocus()
称为Chack,这也解决了这个问题。
答案 1 :(得分:55)
您可以取消注册观察者,然后重新注册。
或者,您可以设置一个标记,以便您的观察者知道您何时自己更改了文本(因此应该忽略它)。
答案 2 :(得分:20)
et_text.addTextChangedListener(new MyTextWatcher(et_text));
用法:
{u'definitions': [{u'text': u'One venerated for experience, judgment, and wisdom.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'Having or exhibiting wisdom and calm judgment.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'Proceeding from or marked by wisdom and calm judgment: sage advice. ', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'Archaic Serious; solemn.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'Any of various plants of the genus Salvia, especially S. officinalis, having aromatic grayish-green, opposite leaves. Also called ramona.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'The leaves of this plant used as a seasoning.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'Any of various similar or related plants in the mint family.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}, {u'text': u'Sagebrush.', u'attribution': u'from The American Heritage\xae Dictionary of the English Language, 4th Edition'}]}
如果您使用 editText.setText()而不是 editable.replace(),则在快速输入文本时可能会感到有些滞后。
答案 3 :(得分:13)
简单的解决方法...... 只要你的逻辑推导出新的编辑文本值是幂等的(它可能会,但只是说)。在侦听器方法中,如果当前值与上次修改值不同,则仅修改编辑文本。
如,
TextWatcher tw = new TextWatcher() {
private String lastValue = "";
@Override
public void beforeTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void onTextChanged(CharSequence charSequence, int i, int i1, int i2) {
}
@Override
public void afterTextChanged(Editable editable) {
// Return value of getNewValue() must only depend
// on the input and not previous state
String newValue = getNewValue(editText.getText().toString());
if (!newValue.equals(lastValue)) {
lastValue = newValue;
editText.setText(newValue);
}
}
};
答案 4 :(得分:3)
如果您需要专注于EditText
更改文字,您可以请求关注。这对我有用:
if (getCurrentFocus() == editText) {
editText.clearFocus();
editText.setText("...");
editText.requestFocus();
}
答案 5 :(得分:2)
我使用这种方式:
mEditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {}
@Override
public void afterTextChanged(Editable s) {
if (mEditText.isFocused()) { //<-- check if is focused
mEditText.setTag(true);
}
}
});
每次您需要以编程方式更改文本时,请先清除焦点
mEditText.clearFocus();
mEditText.setText(lastAddress.complement);
答案 6 :(得分:1)
尝试这个逻辑: 我想setText(&#34;&#34;)而不去无限循环,这段代码适合我。我希望你能修改它以符合你的要求
final EditText text= (EditText)findViewById(R.id.text);
text.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
if(s.toString().isEmpty())return;
text.setText("");
//your code
}
});
答案 7 :(得分:0)
我的变体:
public class CustomEditText extends AppCompatEditText{
TextWatcher l;
public CustomEditText(Context context, AttributeSet attrs) {
super(context, attrs);
}
public void setOnTextChangeListener(TextWatcher l) {
try {
removeTextChangedListener(this.l);
} catch (Throwable e) {}
addTextChangedListener(l);
this.l = l;
}
public void setNewText(CharSequence s) {
final TextWatcher l = this.l;
setOnTextChangeListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
}
});
setText(s);
post(new Runnable() {
@Override
public void run() {
setOnTextChangeListener(l);
}
});
}
}
仅使用setOnTextChangeListener()设置侦听器,并仅使用setNewText设置文本(我想覆盖setText(),但它是最终的)
答案 8 :(得分:0)
我创建了一个抽象类,它减轻了通过TextWatcher对EditText进行修改时的循环问题。
/**
* An extension of TextWatcher which stops further callbacks being called as a result of a change
* happening within the callbacks themselves.
*/
public abstract class EditableTextWatcher implements TextWatcher {
private boolean editing;
@Override
public final void beforeTextChanged(CharSequence s, int start, int count, int after) {
if (editing)
return;
editing = true;
try {
beforeTextChange(s, start, count, after);
} finally {
editing = false;
}
}
abstract void beforeTextChange(CharSequence s, int start, int count, int after);
@Override
public final void onTextChanged(CharSequence s, int start, int before, int count) {
if (editing)
return;
editing = true;
try {
onTextChange(s, start, before, count);
} finally {
editing = false;
}
}
abstract void onTextChange(CharSequence s, int start, int before, int count);
@Override
public final void afterTextChanged(Editable s) {
if (editing)
return;
editing = true;
try {
afterTextChange(s);
} finally {
editing = false;
}
}
public boolean isEditing() {
return editing;
}
abstract void afterTextChange(Editable s);
}
答案 9 :(得分:0)
这是一个方便的类,它提供了一个比TextWatcher更简单的接口,用于希望在发生更改时查看更改的正常情况。它还允许忽略OP请求的下一个更改。
public class EditTexts {
public final static class EditTextChangeListener implements TextWatcher {
private final Consumer<String> onEditTextChanged;
private boolean ignoreNextChange = false;
public EditTextChangeListener(Consumer<String> onEditTextChanged){
this.onEditTextChanged = onEditTextChanged;
}
public void ignoreNextChange(){
ignoreNextChange = true;
}
@Override public void beforeTextChanged(CharSequence __, int ___, int ____, int _____) { }
@Override public void onTextChanged(CharSequence __, int ___, int ____, int _____) { }
@Override public void afterTextChanged(Editable s) {
if (ignoreNextChange){
ignoreNextChange = false;
} else {
onEditTextChanged.accept(s.toString());
}
}
}
}
像这样使用:
EditTexts.EditTextChangeListener listener = new EditTexts.EditTextChangeListener(s -> doSomethingWithString(s));
editText.addTextChangedListener(listener);
每当您想修改editText
的内容而不会导致一连串的递归编辑时,请执行以下操作:
listener.ignoreNextChange();
editText.setText("whatever"); // this won't trigger the listener
答案 10 :(得分:0)
您可以使用Kotlin DSL语法为此提供通用解决方案:
fun TextView.applyWithDisabledTextWatcher(textWatcher: TextWatcher, codeBlock: TextView.() -> Unit) {
this.removeTextChangedListener(textWatcher)
codeBlock()
this.addTextChangedListener(textWatcher)
}
在TextWatcher中,您可以将其用作:
editText.applyWithDisabledTextWatcher(this) {
text = formField.name
}
答案 11 :(得分:0)
这对我有用
EditText inputFileName; // = (EditText)findViewbyId(R.id...)
inputFileName.addTextChangedListener(new TextWatcher() {
public void afterTextChanged(Editable s) {
//unregistering for event in order to prevent infinity loop
inputFileName.removeTextChangedListener(this);
//changing input's text
String regex = "[^a-z0-9A-Z\\s_\\-]";
String fileName = s.toString();
fileName = fileName.replaceAll(regex, "");
s.replace(0, s.length(), fileName); //here is setting new text
Log.d("tag", "----> FINAL FILE NAME: " + fileName);
//registering back for text changes
inputFileName.addTextChangedListener(this);
}
public void beforeTextChanged(CharSequence s, int start, int count, int after) { }
public void onTextChanged(CharSequence s, int start, int before, int count) { }
});
答案 12 :(得分:0)
使用tag
字段可以轻松解决问题,您甚至不必处理editText的焦点。
以编程方式设置文本和标签
editText.tag = "dummyTag"
editText.setText("whatever")
editText.tag = null
检查onTextChanged中的tag
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
if (editText.tag == null) {
// your code
}
}
答案 13 :(得分:0)
非常简单,使用此方法设置文本
document.querySelector('script').addEventListener('beforeinclude', function(e){
//Function executed before each tag like <script src="path/to/jquery.min.js"> be included
})
答案 14 :(得分:0)
这样做很容易
editText.addTextChangedListener(object : TextWatcher {
private var isEditing = false
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
}
override fun afterTextChanged(s: Editable?) {
if(!isEditing){
isEditing = true
editText.setText("Hello World!")
isEditing = false
}
}
})
通过这种方式,它不会无限循环存储
答案 15 :(得分:-2)
您应该确保文本更改的实现是稳定的,并且如果不需要更改则不会更改文本。通常,这将是已经通过观察者一次的任何内容。
最常见的错误是在关联的EditText或Editable中设置新文本,即使文本实际上没有更改。
最重要的是,如果您对可编辑视图进行了更改而不是某些特定视图,则可以轻松地重新使用您的观察者,并且您可以单独使用某些单元测试来测试它,以确保它具有您想要的结果。
由于Editable是一个接口,你甚至可以使用它的虚拟实现,如果在测试应该稳定的内容时调用任何试图改变其内容的方法,则抛出RuntimeException。
答案 16 :(得分:-2)
我做事的方式:
在写段中
EditText e_q;
e_q = (EditText) parentView.findViewWithTag("Bla" + i);
int id=e_q.getId();
e_q.setId(-1);
e_q.setText("abcd...");
e_q.setId(id);
听众
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
int id = view.getId();
if(id==-1)return;
....
仍然可以工作。