我尝试实现fileUpload,但是我收到了下面描述的错误。
我查了this document,但我没有理解我的代码中存在的问题; 问题出在我在代码中标记的第46行。
有人Plz帮我解决问题。
private static final String UPLOAD_DIRECTORY = "d:\\";
public void doPost(HttpServletRequest request,HttpServletResponse response){
ServletFileUpload upload = new ServletFileUpload();
if(ServletFileUpload.isMultipartContent(request)){
FileItemFactory factory = new DiskFileItemFactory();
ServletFileUpload servletFileUpload = new ServletFileUpload(factory);
try {
Line 46---> error List<FileItem> items = upload.parseRequest(request);
for(FileItem item : items){
if( item.isFormField())continue;
String fileName = item.getName();
if (fileName != null) {
fileName = FilenameUtils.getName(fileName);
}
File uploadedFile = new File(UPLOAD_DIRECTORY, fileName);
if (uploadedFile.createNewFile()) {
item.write(uploadedFile);
response.setStatus(HttpServletResponse.SC_CREATED);
response.getWriter().print("The file was created successfully.");
response.flushBuffer();
}else{
throw new IOException("The file already exists in repository.");
}
}
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}else{
try {
response.sendError(HttpServletResponse.SC_UNSUPPORTED_MEDIA_TYPE,"Request contents type is not supported by the servlet" );
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
生成错误:
java.lang.NullPointerException: No FileItemFactory has been set.
at org.apache.commons.fileupload.FileUploadBase.parseRequest(FileUploadBase.java:354)
at org.apache.commons.fileupload.servlet.ServletFileUpload.parseRequest(ServletFileUpload.java:126)
at com.server.FileUpload.doPost(FileUpload.java:46)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:637)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
答案 0 :(得分:3)
在 guess ,这是因为您使用的upload
未使用DiskFileItemFactory
进行初始化,而是servletFileUpload
,而不是{{1}}。