Question

我正在为项目使用spring，hibernate和maven。

我下面有一节课

@Service
public class  ServiceImpl implements Service ,Serializable{
   //Code
}

在这个课程中，我有一个方法声明如下，

@Transactional(rollbackFor = Exception.class, propagation = Propagation.REQUIRES_NEW, readOnly = false)
public void doSomething(Obj a, Obj b){
    //code
}

我对此方法进行了JUnit测试。

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = {"classpath:com/mt/sm/application-context.xml", "classpath:com/mt/sm/security-context.xml"})
@TransactionConfiguration(transactionManager = "transactionManager", defaultRollback = true)
@Transactional
public class ServiceImplTest {
    @Test
    public void testdoSomething() {
        //code
    }
}

我在下面遇到此错误

Testcase: testdoSomething(com.mt.sm.services.ServiceImplTest):  Caused an ERROR
Could not commit JPA transaction; nested exception is javax.persistence.RollbackException: Transaction marked as rollbackOnly org.springframework.transaction.TransactionSystemException: Could not commit JPA transaction; nested exception is javax.persistence.RollbackException: Transaction marked as rollbackOnly

但是我以同样的方式宣布了一个方法来调用上面的那个

public void call (Obj a, Obj b) {
    doSomething(a,b);
}

@Transactional(rollbackFor = Exception.class, propagation = Propagation.REQUIRES_NEW, readOnly = false)
public void doSomething(Obj a, Obj b){
    //code
}

结果，我可以进行测试。我只是想问为什么这样做没有错误。

Answer 1

Spring通过AOP Proxies管理交易，因此内部调用从不是事务性的（您不能代理自己）

JUnit测试，与事务相关的错误

1 个答案: