为什么这个SQL会出现语法错误？

Question

尝试查看哪些视频类别“me_id”和“you_id”都观看了：

SELECT c.title, COUNT(*) AS popularity 
FROM video v 
JOIN user u ON v.user_id = u.id 
JOIN v_cat vc ON c.id = vc.vid_id 
JOIN cat c ON c.id = vc.cat_id
JOIN u_cat uc ON uc.cat_id = c.id  
WHERE uc.user_id = '$me_id'

INTSERSECT 

SELECT c.title, COUNT(*) AS popularity 
FROM video v 
JOIN user u ON v.user_id = u.id 
JOIN v_cat vc ON c.id = vc.vid_id 
JOIN cat c ON c.id = vc.cat_id
JOIN u_cat uc ON uc.cat_id = c.id  
WHERE uc.user_id = '$you_id'

GROUP BY c.title 
ORDER BY uc.id DESC LIMIT 0, 10

我正在使用PHP / MYSQL的任何想法？

Answer 1

MySQL doesn't have INTERSECT.

Answer 2

JOIN JOIN，这是有效的语法吗？

Answer 3

FROM video v JOIN JOIN v_cat vc ON c.id = vc.vid_id

在上面这行你必须使用加入一次..

Answer 4

我在你的第一个选择中看到两个连续的JOIN关键字，但没有任何错误信息，这将很难调试。

Answer 5

而不是INTERSECT，你可以使用关键词UNION或UNION ALL，这基本上会做交叉选择。见http://dev.mysql.com/doc/refman/5.0/en/union.html