Question

我有一个使用C＃编写的简单应用程序，它通过命令行参数接受操作数，并通过退出代码报告成功或失败。通过批处理文件在Windows XP上运行时：

MyProg.exe ...//Snip: Command-line Params ...
echo %errorlevel%;

返回的退出代码是应用程序设置的值。但是，当使用bash-script在Linux上调用相同的应用程序时：

mono MyProg.exe ...//Snip: Command-line Params ...
echo $?;

报告给shell的退出代码始终为零，而不是应用程序设置的值。是否有任何方法可以捕获应用程序设置的退出代码，然后由mono修改？

我尝试过使用Environment.Exit()和Application.Exit()，这个问题似乎没什么区别。此外，应用程序在调用退出函数之前显式设置Environment.ExitCode。

这是一个简单的WinForms应用程序，可以重现这种行为：

using System;
using System.Drawing;
using System.Windows.Forms;

namespace ConsoleTest
{
 public class Form1 : Form
 {
    private System.Windows.Forms.Button button1;
    private System.Windows.Forms.Button button2;

  public Form1()
  {
     #region Create UI Stuff
     this.button1 = new System.Windows.Forms.Button();
     this.button2 = new System.Windows.Forms.Button();
     this.SuspendLayout();
     // 
     // button1
     // 
     this.button1.Location = new System.Drawing.Point(114, 22);
     this.button1.Name = "button1";
     this.button1.Size = new System.Drawing.Size(75, 23);
     this.button1.TabIndex = 0;
     this.button1.Text = "ExitZero";
     this.button1.UseVisualStyleBackColor = true;
     this.button1.Click += new System.EventHandler(this.button1_Click);
     // 
     // button2
     // 
     this.button2.Location = new System.Drawing.Point(114, 70);
     this.button2.Name = "button2";
     this.button2.Size = new System.Drawing.Size(75, 23);
     this.button2.TabIndex = 0;
     this.button2.Text = "ExitOne";
     this.button2.UseVisualStyleBackColor = true;
     this.button2.Click += new System.EventHandler(this.button2_Click);
     // 
     // Form1
     // 
     this.AutoScaleDimensions = new System.Drawing.SizeF(6F, 13F);
     this.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Font;
     this.ClientSize = new System.Drawing.Size(310, 136);
     this.Controls.Add(this.button2);
     this.Controls.Add(this.button1);
     this.Name = "Form1";
     this.Text = "Form1";
     this.ResumeLayout(false);
     #endregion
  }

  private void button1_Click(object sender, EventArgs e)
  {
     Environment.ExitCode = 0;
     //Environment.Exit(0);
     Application.Exit();
  }

  private void button2_Click(object sender, EventArgs e)
  {
     Environment.ExitCode = 1;
     //Environment.Exit(1);
     Application.Exit();
  }
 }
}

Answer 1

Mono不会重写任何内容。我的测试应用程序：

pakrym@ubuntu:/home/pakrym# cat exit.cs 
class Program
{
 public static void Main()
 {
      System.Environment.Exit(1);
 }
}
pakrym@ubuntu:/home/pakrym# mono ./exit.exe 
pakrym@ubuntu:/home/pakrym# echo $?
1
pakrym@ubuntu:/home/pakrym# mono --version
Mono JIT compiler version 2.6.7 (Debian 2.6.7-5ubuntu3)
Copyright (C) 2002-2010 Novell, Inc and Contributors. www.mono-project.com
    TLS:           __thread
GC:            Included Boehm (with typed GC and Parallel Mark)
SIGSEGV:       altstack
Notifications: epoll
Architecture:  x86
Disabled:      none

保留Mono中的退出代码

1 个答案: