Question

我的表结构（MySQL /每个都与下面相同）

+-------+--------------+------+------+-------------------+
| Field | Type         | Null | Key  | Default           |
+-------+--------------+------+------+-------------------+
| id    | int(11)      | NO   | PRI  | AUTO INCREMENT    | 
| lesson| varchar(255) | NO   |      | LESSON_NAME       | 
| exam  | char(50)     | NO   |UNIQUE| NO DEFAULT        |
| quest | text         | NO   |      | NO DEFAULT        |
| answer| text         | NO   |      | NO DEFAULT        |
| note  | text         | NO   |      | NO DEFAULT        |
+-------+--------------+------+------+-------------------+

并且我发布了一些值来通过ajax（$ post）添加此表 - PHP 5.0
在database.php中有一个函数来获取发布的数据并添加到表

function update_table ($proper_table, $name, $question, $answer, $note) {
$sql = "INSERT INTO $proper_table (id, lesson, exam, quest, answer, note) VALUES ('', '', $name, $question,$answer,$note) ON DUPLICATE KEY UPDATE exam = $name, quest = $question, answer = $answer, note = $note";
$result= mysql_query($sql)or die(mysql_error());
}

$ proper_table变量由另一个变量获取，以将此记录添加到正确的表中（注意：原始表格字段和变量是不同的（土耳其语），更易于理解我翻译成英语但语法与您看到的相同。）

问题：我想检查是否有记录表示考试字段相同，则所有这些变量都将用于更新此记录，否则让函数将此记录作为新记录放入正确的表中。
但我得到的错误如下

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near

有没有错误的编码？什么可以解决方案？
谢谢你......

Answer 1

function update_table ($proper_table, $name, $question, $answer, $note) {
    $sql = "INSERT INTO $proper_table (lesson, exam, quest, answer, note) VALUES ('', '$name', '$question','$answer','$note') ON DUPLICATE KEY UPDATE quest = VALUES(quest), answer = VALUES(answer), note = VALUES(note)";
   $result= mysql_query($sql)or die(mysql_error());
}

刚刚解决这个问题我将详细介绍这些变化

$sql = "INSERT INTO $proper_table 

// Removed the PK AI field - don't need to specify this
(lesson, exam, quest, answer, note)     

// Likewise removed PK field, and added quotes around the text fields
VALUES ('', '$name', '$question','$answer','$note')    
ON DUPLICATE KEY UPDATE 

// If you specify VALUES(fieldName) it will update with the value you specified for the field in the conflicting row
// Also removed the exam update, as exam is the UNIQUE key which could cause conflicts so updating that would have no effect
quest = VALUES(quest), answer = VALUES(answer), note = VALUES(note)";

Answer 2

例如，您需要在SQL '$name'中用单引号将字符串变量包装起来。否则mysql认为你引用的是列名。

Answer 3

使用该查询，当您添加ON DUPLICATE KEY UPDATE ...当id与您发送的id相同时，它将更新，在这种情况下，您不会发送id作为参数，因此它永远不会更新因为你有自动增量的id。

解决方案可能是您阅读了表格，其中考试等于您要发送的参数，如下所示：

    SELECT id FROM $proper_table;

如果它为null，则执行插入，如果它不为null，则更新将参数作为参数从选择中获取

Answer 4

id自动递增，因此您可能不希望将空字符串设置为id。

尝试：

$sql = "INSERT INTO $proper_table (lesson, exam, quest, answer, note) VALUES ('', $name, $question,$answer,$note) ON DUPLICATE KEY UPDATE exam = $name, quest = $question, answer = $answer, note = $note";

Answer 5

你必须这样做

<?php
function update_table($proper_table, $name, $question, $answer, $note, $id) {

    $sqlQuery = "INSERT INTO '".$proper_table."' SET
                    name        =       '".$name."',
                    question        =   '".$question."',
                    answer      =       '".$answer."',
                    note        =       '".$note."' WHERE id = '".$id."'";

    $result= mysql_query($sqlQuery)or die(mysql_error());

}
?>

INSERT INTO的正确语法是什么...在MySQL中的DUPLICATE KEY UPDATE？

5 个答案: