HttpWebRequest - ASP .NET MVC 3传递会话状态

时间:2012-02-20 18:53:18

标签: asp.net-mvc session

我需要获取控制器/操作的HTML标记才能生成PDF。我所做的是:

    public ActionResult Index()
    {
        Session["Message"] = "SESSION-MESSAGE";

        String URL = "http://localhost:7401/Home/SuperComplex";

        HttpWebRequest req = (HttpWebRequest)WebRequest.Create(URL);
        req.CookieContainer = new CookieContainer();

        for (int i = 0; i <= this.Request.Cookies.Count - 1; i++)
            req.CookieContainer.Add(
                new System.Net.Cookie(
                    name: this.Request.Cookies[i].Name,
                    value: Request.Cookies[i].Value,
                    path: Request.Cookies[i].Path, domain: this.HttpContext.Request.Url.Host)
                );

        using (var r = req.GetResponse())
        {
            using (var s = new StreamReader(r.GetResponseStream()))
            {
                var htmlToPrint = s.ReadToEnd();
                Response.Write("<h1>" + htmlToPrint + "</h1>");
            }
        }

        return View();
    }

考虑到上述情况,在SuperComplex会话中,我应该有Session [“Message”]。但由于一些奇怪的原因,它不会去那里。

我已经检查过Session.SessionId - 在两种情况下它都是相同的。

此外,在第二次或第三次请求时,请求超时!

再次:http://localhost:7401/(S(SESSION_ID))/Home/About

如果在其他浏览器中请求:会话劫持确实发生 - 但WebRequest死了! :(

帮助 - 有人吗?

1 个答案:

答案 0 :(得分:2)

将HTML存储在Partial View中,然后使用Helper函数将其解析为字符串。

// usage
/*
 * http://stackoverflow.com/questions/4344533/asp-net-mvc-razor-how-to-render-a-razor-partial-views-html-inside-the-controll
 * 
    var model = _repository.Find(x => x.PropertyID > 3).FirstOrDefault();
    var test = this.RenderViewToString("DataModel", model);
    return Content(test);
 */

public static string RenderPartialToString<T>(this ControllerBase controller, string partialName, T model)
{
    var vd = new ViewDataDictionary(controller.ViewData);
    var vp = new ViewPage
    {
        ViewData = vd,
        ViewContext = new ViewContext(),
        Url = new UrlHelper(controller.ControllerContext.RequestContext)
    };

    ViewEngineResult result = ViewEngines
                              .Engines
                              .FindPartialView(controller.ControllerContext, partialName);

    if (result.View == null)
    {
        throw new InvalidOperationException(
        string.Format("The partial view '{0}' could not be found", partialName));
    }
    var partialPath = ((RazorView)result.View).ViewPath;

    vp.ViewData.Model = model;

    using(StringWriter sw = new StringWriter()) {
        ViewContext viewContext = new ViewContext(controller.ControllerContext, result.View, vd, controller.TempData, sw);
        result.View.Render(viewContext, sw);

        return sw.GetStringBuilder().ToString();
    }
}