使用boost library c ++搜索目录和子目录中的文件

时间:2012-02-20 17:59:42

标签: c++ search boost unicode filesystems

我想创建一个应用程序,使用c ++的boost库搜索目录和子目录中的文件,我也不想让像UNICODE文件这样名为arabic的文件出错。 那我怎么能这样做呢?

更新

#include <iostream>
#include <boost/filesystem/operations.hpp>
#include <boost/filesystem/fstream.hpp>
#define BOOST_FILESYSTEM_NO_DEPRECATED
using namespace boost::filesystem;
using namespace std;

bool find_file( const path & dir_path,         // in this directory,
                const std::string & file_name, // search for this name,
                path & path_found )            // placing path here if found
{
  if ( !exists( dir_path ) ) return false;
  directory_iterator end_itr; // default construction yields past-the-end
  for ( directory_iterator itr( dir_path );
        itr != end_itr;
        ++itr )
  {
    if ( is_directory(itr->status()) )
    {
      if ( find_file( itr->path(), file_name, path_found ) ) return true;
    }
    else if ( itr->path().filename() == file_name ) // see below
    {
      path_found = itr->path();
      return true;
    }
  }
  return false;
}

int main()
{
    path myPath = "C:";
    string myFile = ".doc";
    path myfound = "c:";

    find_file(myPath, myFile, myfound);
}

我也尝试了这段代码,但它不会编译它显示此错误和很多

undefined reference to `boost::filesystem3::path::filename() const

也:

X:\mingw\boost\boost_1_47_0\boost\system\error_code.hpp|214|undefined reference to `boost::system::generic_category()'|

1 个答案:

答案 0 :(得分:10)

您必须链接boost_system和boost_filesystem库。如何执行此操作取决于您的编译器/链接器组合;例如,在我的系统上,我必须添加标志-lboost_system-mt -lboost_filesystem-mt

一些评论:在Windows上,您通常需要wstring(或其他“宽字符”对象)来增加使用Unicode路径的机会。其次,您可以使用find_ifrecursive_directory_iterator

缩短代码
#include <algorithm>
#include <iostream>

#define BOOST_FILESYSTEM_NO_DEPRECATED
#define BOOST_FILESYSTEM_VERSION 3

#include <boost/filesystem.hpp>

using namespace std;
using namespace boost::filesystem;

bool find_file(const path& dir_path, const path& file_name, path& path_found) {
  const recursive_directory_iterator end;
  const auto it = find_if(recursive_directory_iterator(dir_path), end,
                          [&file_name](const directory_entry& e) {
                            return e.path().filename() == file_name;
                          });
  if (it == end) {
    return false;
  } else {
    path_found = it->path();
    return true;
  }
}

int main() {
  const path myPath = L"/usr/local";
  const path myFile = L"filesystem.hpp";
  path myFound;
  find_file(myPath, myFile, myFound);
  wcout << myFound << endl;
}

我的示例使用C ++ 11功能autolambda,它们存在于GCC 4.6中。如果你的编译器没有这些,你可以很容易地用谓词对象替换lambda,用显式类型说明符替换auto

#include <functional>

class file_name_equal: public unary_function<path, bool> {
public:
  explicit file_name_equal(const path& fname): file_name(fname) { }

  bool operator()(const directory_entry& entry) const {
    return entry.path().filename() == file_name;
  }

private:
  path file_name;
};

bool find_file_cxx03(const path& dir_path, const path& file_name,
                     path& path_found) {
  const recursive_directory_iterator end;
  const recursive_directory_iterator it =
    find_if(recursive_directory_iterator(dir_path), end,
            file_name_equal(file_name));
  if (it == end) {
    return false;
  } else {
    path_found = it->path();
    return true;
  }
}

另一个不错的变体使用Boost.Optional删除了返回值引用:

...
#include <boost/optional.hpp>

using namespace std;
using namespace boost;
using namespace boost::filesystem;

optional<path> find_file(const path& dir_path, const path& file_name) {
  const recursive_directory_iterator end;
  const auto it = find_if(recursive_directory_iterator(dir_path), end,
                          [&file_name](const directory_entry& e) {
                            return e.path().filename() == file_name;
                          });
  return it == end ? optional<path>() : it->path();
}

int main() {
  const path myPath = L"/usr/local";
  const path myFile = L"filesystem.hpp";
  wcout << find_file(myPath, myFile).get_value_or("not found") << endl;
}