我正在尝试在HttpPost对象中设置一些Http参数。
HttpPost post=new HttpPost(url);
HttpParams params=new BasicHttpParams();
params.setParameter("param", "value");
post.setParams(params);
HttpResponse response = client.execute(post);
看起来根本没有设置参数。你知道为什么会这样吗?
谢谢
答案 0 :(得分:26)
对于那些希望使用HttpGet找到答案的人,这里有一个(来自https://stackoverflow.com/a/4660576/330867):
StringBuilder requestUrl = new StringBuilder("your_url");
String querystring = URLEncodedUtils.format(params, "utf-8");
requestUrl.append("?");
requestUrl.append(querystring);
HttpClient httpclient = new DefaultHttpClient();
HttpGet get = new HttpGet(requestUrl.toString());
注意:这不考虑your_url
的状态:如果已经有一些参数,如果它已经包含“?”等,我假设你知道如何编码/搜索并适应您的情况。
答案 1 :(得分:8)
HttpPost httpPost = new HttpPost(url);
List<NameValuePair> nvps = new ArrayList<NameValuePair>();
nvps.add(new BasicNameValuePair("param", "value"));
httpPost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
httpClient.execute(httpPost);