我想在目录中的文件夹中显示10-15个图像,但我不想重复显示它们。我也不想使用MySQL Table
请帮忙。
目前我正在使用以下代码
$imglist='';
$img_folder = "gallerypage/small/";
mt_srand((double)microtime()*1000);
$imgs = dir($img_folder);
while ($file = $imgs->read()) {
$imglist .= "$file"."|";
} closedir($imgs->handle);
$imglist = explode("|", $imglist);
//print_r($imglist);
$no = sizeof($imglist)-2;
//echo $no;
for ($i=0; $i<=$no; $i++)
{
$random = $i; // mt_rand($i, $no/$i);
//echo $random;
$fileb =
$image = $imglist[$i];
$fileb = $image;
if($image != '.' && $image != '..' && $image != 'Thumbs.db' )
{
//echo '<img src="'.$img_folder.$image.'" border=0>';
//if($image != ""){
//echo "k".$image."k";
echo "<a href='".$img_folderb.$fileb."' rel='lightbox-journey'><img src='".$img_folder.$image."' title='".$image."' alt='".$image."' height='100'/>";
//}
}
}
答案 0 :(得分:3)
您可以为图像添加文件夹并迭代,直到达到15,不会重复
$all_images = glob("/your/directory/{*.jpg, *.JPG, *.JPEG, *.png, *.PNG}", GLOB_BRACE);
// shuffle($all_images); // uncomment this line to randomize the images
$images = array();
foreach ($all_images as $index => $image) {
if ($index == 15) break; // Only print 15 images
$image_name = basename($image);
echo "<img src='/public/directory/{$image_name}' />";
}
答案 1 :(得分:3)
<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
// Set up the image files to be used.
var theImages = new Array() // do not change this
// To add more image files, continue with the
// pattern below, adding to the array.
theImages[0] = '1.gif'
theImages[1] = '2.gif'
theImages[2] = '3.gif'
theImages[3] = '4.gif'
// do not edit anything below this line
var j = 0
var p = theImages.length;
var preBuffer = new Array()
for (i = 0; i < p; i++){
preBuffer[i] = new Image()
preBuffer[i].src = theImages[i]
}
var whichImage = Math.round(Math.random()*(p-1));
function showImage(){
document.write('<img src="'+theImages[whichImage]+'">');
}
// End -->
</script>
</HEAD>
<!-- STEP TWO: Copy this code into the BODY of your HTML document -->
<BODY>
<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
showImage();
// End -->
</script>
<p><center>
<font face="arial, helvetica" size"-2">Free JavaScripts provided<br>
Master</font>
</center><p>
答案 2 :(得分:1)
$images = glob('/path/to/image/dir/{*.jpg,*.png,*.gif}', GLOB_BRACE);
foreach(array_rand($images,10) as $key) //display 10 image
{
echo '<img src="'.$images[$key].'" />';
}
答案 3 :(得分:0)
您可以从目录中读取文件并将其存储到数组中,然后将数组洗牌并获取前10项:
$files = array();
$handle=opendir(".");
while (($file = readdir($handle))!==false) {
if(is_file($file))
$files[] = $file;
}
shuffle($files);
$ctr = 0;
foreach($files as $f)
{
//process file here
if($ctr++>=10)
break;
}