Question

我面临着奇怪的问题。在2008版和VS 2010 调试和Dubug Unicode 版本中，代码工作正常，但无法在发布和发布Unicode 中编译。可能是什么原因。

此代码正在生成错误

struct bitset_extractor
{
    typedef std::forward_iterator_tag   iterator_category;
    typedef T                           value_type;
    typedef T*                          pointer;
    typedef T&                          reference;
    typedef ptrdiff_t                   difference_type;

    bitset_extractor(const boost::dynamic_bitset<T>& bs, T *buffer)
        : bs_(bs), buffer_(buffer), current_(0)
    {}

    bitset_extractor(const bitset_extractor& it)
        : bs_(it.bs_), buffer_(it.buffer_), current_(it.current_)
    {}

    T& operator*()
    {
        return buffer_[current_];
    }

    bitset_extractor& operator++()
    {
        ++current_;
        return *this;
    }
   private:
    void operator=(T const&);           // unimplemented

    const boost::dynamic_bitset<T>&     bs_;
    T * const                           buffer_;
    unsigned int                        current_;
};

1>C:\Program Files\Microsoft Visual Studio 10.0\VC\include\xutility(275): error C2679: binary '=' : no operator found which takes a right-hand operand of type 'bitstream::bitset_extractor<T>' (or there is no acceptable conversion)
1>          with
1>          [
1>              T=uint8_t
1>          ]
1>           C:\vikram\Project\Seurat\src\app\logitech\LogiRTP\Library\Filters\plc\common\bitstream.h(195): could be 'void bitstream::bitset_extractor<T>::operator =(const T &)'
1>          with
1>          [
1>              T=uint8_t
1>          ]
1>          while trying to match the argument list '(bitstream::bitset_extractor<T>, bitstream::bitset_extractor<T>)'
1>          with
1>          [
1>              T=uint8_t
1>          ]
1>          C:\Program Files\Microsoft Visual Studio 10.0\VC\include\xutility(2176) : see reference to function template instantiation '_Iter &std::_Rechecked<_OutIt,_OutIt>(_Iter &,_UIter)' being compiled
1>          with
1>          [
1>              _Iter=bitstream::bitset_extractor<uint8_t>,
1>              _OutIt=bitstream::bitset_extractor<uint8_t>,
1>              _UIter=bitstream::bitset_extractor<uint8_t>
1>          ]
1>          C:\vikram\Project\Seurat\3rdparty\boost\boost/dynamic_bitset/dynamic_bitset.hpp(1090) : see reference to function template instantiation '_OutIt std::copy<std::_Vector_const_iterator<_Myvec>,BlockOutputIterator>(_InIt,_InIt,_OutIt)' being compiled
1>          with
1>          [
1>              _OutIt=bitstream::bitset_extractor<uint8_t>,
1>              _Myvec=std::_Vector_val<unsigned char,std::allocator<uint8_t>>,
1>              BlockOutputIterator=bitstream::bitset_extractor<uint8_t>,
1>              _InIt=std::_Vector_const_iterator<std::_Vector_val<unsigned char,std::allocator<uint8_t>>>
1>          ]
1>          C:\vikram\Project\Seurat\src\app\logitech\LogiRTP\Library\Filters\plc\common\bitstream.h(210) : see reference to function template instantiation 'void boost::to_block_range<uint8_t,std::allocator<_Ty>,bitstream::bitset_extractor<T>>(const boost::dynamic_bitset<Block> &,BlockOutputIterator)' being compiled
1>          with
1>          [
1>              _Ty=uint8_t,
1>              T=uint8_t,
1>              Block=uint8_t,
1>              BlockOutputIterator=bitstream::bitset_extractor<uint8_t>
1>          ]
1>C:\Program Files\Microsoft Visual Studio 10.0\VC\include\xutility(275): error C2582: 'operator =' function is unavailable in 'bitstream::bitset_extractor<T>'
1>          with
1>          [
1>              T=uint8_t
1>          ]

Answer 1

问题是你的bitset_extractor被用作迭代器，但它不能满足迭代器的所有要求。

std::copy函数在尝试将原始迭代器转换为已检查的迭代器时，使用两个operator=对象调用bitset_extractor<uint8_t>。由于用户定义的迭代器不存在已检查的迭代器，因此检查的迭代器类型和原始迭代器类型是相同的，从而导致正在使用的迭代器的常规副本。

罪魁祸首是_Rechecked函数，用于将常规迭代器转换为已检查的迭代器。这取决于迭代器调试级别，以不同方式完成;这就是你的Debug构建工作的原因，但不是你的Release版本，因为它们默认具有不同的迭代器调试级别。

解决方案是为operator=实施bitset_extractor。如果要将它用作迭代器，必须支持其类型的迭代器所需的所有功能。

禁用已检查的迭代器无济于事。无论你做什么，你的迭代器仍将通过_Rechecked函数。

Answer 2

问题解决了。我在VS Project Setting-＆gt;预处理器中添加了_SECURE_SCL = 1。

工作正常。

错误C2582：'bitstream :: bitset_extractor <t> VS 2010 </t>中'operator ='功能不可用

2 个答案: