我想在值为1时将gridview列的值更改为active。 我有像
这样的gridview列<asp:BoundField DataField="STATUS" HeaderText="STATUS" SortExpression="STATUS" HeaderStyle-HorizontalAlign="Left">
<HeaderStyle HorizontalAlign="Left"></HeaderStyle>
</asp:BoundField>
和cs代码
protected void gvCategory_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
if (e.Row.Cells[5].Text=="0")
{
e.Row.Cells[5].Text = "INACTIVE";
}
}
}
这是有效但如果我更改列顺序则会失败。 我需要的是像findControl函数。 感谢。
答案 0 :(得分:15)
以下是我多年前写的一些可能对您有用的实用程序:
// ---- GetCellByName ----------------------------------
//
// pass in a GridViewRow and a database column name
// returns a DataControlFieldCell or null
static public DataControlFieldCell GetCellByName(GridViewRow Row, String CellName)
{
foreach (DataControlFieldCell Cell in Row.Cells)
{
if (Cell.ContainingField.ToString() == CellName)
return Cell;
}
return null;
}
// ---- GetColumnIndexByHeaderText ----------------------------------
//
// pass in a GridView and a Column's Header Text
// returns index of the column if found
// returns -1 if not found
static public int GetColumnIndexByHeaderText(GridView aGridView, String ColumnText)
{
TableCell Cell;
for (int Index = 0; Index < aGridView.HeaderRow.Cells.Count; Index++)
{
Cell = aGridView.HeaderRow.Cells[Index];
if (Cell.Text.ToString() == ColumnText)
return Index;
}
return -1;
}
// ---- GetColumnIndexByDBName ----------------------------------
//
// pass in a GridView and a database field name
// returns index of the bound column if found
// returns -1 if not found
static public int GetColumnIndexByDBName(GridView aGridView, String ColumnText)
{
System.Web.UI.WebControls.BoundField DataColumn;
for (int Index = 0; Index < aGridView.Columns.Count; Index++)
{
DataColumn = aGridView.Columns[Index] as System.Web.UI.WebControls.BoundField;
if (DataColumn != null)
{
if (DataColumn.DataField == ColumnText)
return Index;
}
}
return -1;
}
答案 1 :(得分:3)
您可以循环所有列以获取正确的索引或使用此LINQ:
String colToFind = "status";
int colIndex = ((GridView)sender).Columns.Cast<DataControlField>()
.Where((c, index) => c.HeaderText.ToLower().Equals(colToFind))
.Select((c,index)=>index).First();
答案 2 :(得分:0)
更清洁更容易阅读LINQ。蒂姆不适合我。
private int GetFirstGridViewColIndex(string dataField, object sender)
{
var boundFieldColumns = ((GridView)sender).Columns.Cast<BoundField>();
return boundFieldColumns.Where((column, index) => string.Equals(column.DataField, dataField, StringComparison.InvariantCultureIgnoreCase))
.Select((column, index) => index)
.First();
}