Question

我正在尝试构建一个包含两个交叉表和多列的表。到目前为止我有这个，当我运行它时

    create table test2(city nvarchar(10), race nvarchar(30), sex nvarchar(10), age int)
    insert into test2 values ('Austin',  'African-American', 'male', 21)
    insert into test2 values ('Austin',  'Asian', 'female', 22)
    insert into test2 values ('Austin',  'Caucasian', 'male', 23)
    insert into test2 values ('Austin',  'Hispanic', 'female', 24)
    insert into test2 values ('Austin',  'African-American', 'Unknown', 25)
    insert into test2 values ('Austin',  'Asian', 'male', 26)
    insert into test2 values ('Austin',  'Caucasian', 'female', 27)
    insert into test2 values ('Austin',  'Hispanic', 'Unknown', 28)
    insert into test2 values ('Austin',  'Asian', 'male', 29)
    insert into test2 values ('Austin',  'Caucasian', 'female', 31)
    insert into test2 values ('Dallas',  'Hispanic', 'Unknown', 32)
    insert into test2 values ('Dallas',  'African-American', 'male', 33)
    insert into test2 values ('Dallas',  'Asian', 'female', 34)
    insert into test2 values ('Dallas',  'Caucasian', 'Unknown', 35)
    insert into test2 values ('Dallas',  'Hispanic', 'male', 500)
    insert into test2 values ('Dallas',  'African-American', 'female', 36)
    insert into test2 values ('Dallas',  'Asian', 'Unknown', 37)
    insert into test2 values ('Dallas',  'Caucasian', 'male', 38)
    insert into test2 values ('Dallas',  'Hispanic', 'female', 39)
    insert into test2 values ('Dallas',  'African-American', 'Unknown', 41)
    insert into test2 values ('Houston',  'Asian', 'male', 42)
    insert into test2 values ('Houston',  'Caucasian', 'female', 43)
    insert into test2 values ('Houston',  'Hispanic', 'Unknown', 44)
    insert into test2 values ('Houston',  'African-American', 'male', 45)
    insert into test2 values ('Houston',  'Asian', 'female', 46)
    insert into test2 values ('Houston',  'Caucasian', 'Unknown', 47)
    insert into test2 values ('Houston',  'Hispanic', 'male', 48)
    insert into test2 values ('Houston',  'African-American', 'female', 49)
    insert into test2 values ('Houston',  'Asian', 'Unknown', 51)
    insert into test2 values ('Houston',  'Caucasian', 'male', 52)

    SELECT  *
    FROM
    (
    SELECT  a.city, a.sex
    FROM [AdventureWorksDW].[dbo].[test2] a

    ) p
    PIVOT
    (
    COUNT (sex)
    FOR sex
    IN ([male], [female], [Unknown])
    ) AS pvt

我明白了

s http://realestateagenthealthinsurance.com/images/111.jpg

但我需要的是这个，顶部有两个交叉标签，多个列有一个选项。

s http://realestateagenthealthinsurance.com/images/222.jpg

这可以通过枢轴或任何其他解决方案吗？提前致谢

Answer 1

您可以为3个年龄组中的每一个运行单独的PIVOT查询，然后将结果外部加入到城市和性别的查询中：

WITH DataKeys AS (
    select distinct city, sex
    from test2),
Data20to29 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 20 and 29
    ) AS Age20to29
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data20to29),
Data30to39 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 30 and 39
    ) AS Age30to39
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data30to39),
Data40to49 AS (
    SELECT *
    FROM(SELECT * FROM test2 WHERE age between 40 and 49
    ) AS Age40to49
    PIVOT (COUNT(age)
           FOR race IN ([African-American], [Asian], [Caucasian], [Hispanic])
    ) as Data40to49)
SELECT SELECT k.city, k.sex,
   d20.[African-American], d20.Asian, d20.Caucasian, d20.Hispanic,
   d30.[African-American], d30.Asian, d30.Caucasian, d30.Hispanic,
   d40.[African-American], d40.Asian, d40.Caucasian, d40.Hispanic
FROM DataKeys k LEFT JOIN Data20to29 d20 ON d20.city = k.city AND d20.sex = k.sex
LEFT JOIN Data30to39 d30 ON d30.city = k.city AND d30.sex = k.sex
LEFT JOIN Data40to49 d40 ON d40.city = k.city AND d40.sex = k.sex
ORDER BY k.city, k.sex

Answer 2

WITH T AS (
    SELECT A.city,
           A.sex, 
           CASE
                WHEN A.age BETWEEN 20 AND 30 THEN '20-30_' + race
                WHEN A.age BETWEEN 31 AND 40 THEN '31-40_' + race
                WHEN A.age BETWEEN 41 AND 50 THEN '41-50_' + race
           END AS age_range_race
    FROM @test2 AS A
)
SELECT  *
FROM T
PIVOT( COUNT(age_range_race) FOR age_range_race
       IN(
          [20-30_African-American], 
          [20-30_Asian], 
          [20-30_Caucasian], 
          [20-30_Hispanic],
          [31-40_African-American], 
          [31-40_Asian], 
          [31-40_Caucasian], 
          [31-40_Hispanic],
          [41-50_African-American], 
          [41-50_Asian], 
          [41-50_Caucasian], 
          [41-50_Hispanic]
          )
) AS P
ORDER BY city, sex

Sql Pivot表有两个交叉表和多列

2 个答案: