学习使用Ruby Threads在不同操作系统平台之间传输代码。
问题是控制台被冻结,直到non_join1完成,这也阻止了non_join2的启动。 non_join1等待join命令,直到线程完成。
该软件需要独立运行多个例程。主程序是一个独立的程序,可以实时运行收集数据。收集的数据将写入文件。使用Threads的不同程序并行处理数据。启动/停止和状态由主控制台控制。
启动分析数据文件并从线程获取状态所需的单独程序的最佳ruby方法是什么?
感谢, PB
# This is the console that starts up the multiple threads.
#!/usr/bin/ruby
loop do
puts " input a command"
command = gets.chop!
control = case command
when "1" : "1"
when "2" : "2"
end
if control == "1" then
puts `date`+ "routine 1"
puts `./non_join1.rb`
puts `date`
end
if control == "2" then
puts `date` + "routine 2"
`./non_join2.rb`
end
end
#!/usr/bin/ruby
# Example of worker program 1 used to process data files
#file non_join1.rb
x = Thread.new { sleep 0.1; print "xxxxxxxxx"; print "yyyyyyyyyyy"; print "zzzzzzzzzz" }
a = Thread.new { print "aaaaaaaaa"; print "bbbbbbbbbb"; sleep 0.1; print "cccccccc" }
puts " "
(1..10).each {|i| puts i.to_s+" done #{i}"}
x.join
a.join
sleep(30)
#!/usr/bin/ruby
# Example of worker program 2 used to process data files
#file non_join2.rb
x = Thread.new { sleep 0.1; print "xxxxxxxxx"; print "yyyyyyyyyyy"; print "zzzzzzzzzz" }
a = Thread.new { print "aaaaaaaaa"; print "bbbbbbbbbb"; sleep 0.1; print "cccccccc" }
x.join
a.join
$ ./call_ruby.rb
input a command
1
Sat Feb 18 10:36:43 PST 2012
routine 1
aaaaaaaaabbbbbbbbbb
1 done 1
2 done 2
3 done 3
4 done 4
5 done 5
6 done 6
7 done 7
8 done 8
9 done 9
10 done 10
xxxxxxxxxyyyyyyyyyyyzzzzzzzzzzcccccccc
Sat Feb 18 10:37:13 PST 2012
input a command
答案 0 :(得分:1)
使用例如此函数,而不是执行``尝试此分叉(创建新进程):
class Execute
def self.run(command)
pid = fork do
Kernel.exec(command)
end
return pid
end
end
您的代码看起来像
loop do
puts " input a command"
command = gets.chop!
control = case command
when "1" : "1"
when "2" : "2"
end
if control == "1" then
puts `date`+ "routine 1"
Execute.run("./non_join1.rb")
puts `date`
end
if control == "2" then
puts `date` + "routine 2"
Execute.run("./non_join2.rb")
end
end