通过xml我可以在ActionBar
。
main_menu.xml:
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<item android:id="@+id/menu_new_form"
android:icon="@drawable/ic_new_form"
android:title="@string/menu_new_form"
android:showAsAction="ifRoom|withText">
<menu>
<item android:id="@+id/form1"
android:icon="@drawable/attachment"
android:title="Form 1"
android:onClick="onSort" />
<item android:id="@+id/form2"
android:icon="@drawable/attachment"
android:title="Form 2"
android:onClick="onSort" />
</menu>
</item>
</menu>
但是如何通过Java代码添加这些子项?它不能工作如下,子项被添加到错误的操作(也没有显示drawable),非常正确的按钮,而不是我的'新表单'按钮:
main_menu.xml:
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<item android:id="@+id/menu_new_form"
android:icon="@drawable/ic_new_form"
android:title="@string/menu_new_form"
android:showAsAction="ifRoom|withText">
</item>
</menu>
Java代码:
@Override
public boolean onCreateOptionsMenu(Menu menu) {
super.onCreateOptionsMenu(menu);
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.main_menu, menu);
Log.d("MainMenu", ",menu title0: " + menu.getItem(0).getTitle());
// returns "New Form"
menu.addSubMenu(0, Menu.NONE, 1, "Form 1").setIcon(R.drawable.attachment);
menu.addSubMenu(0, Menu.NONE, 2, "Form 2").setIcon(R.drawable.attachment);
return true;
}
有没有办法实现这一点,通过Java代码而不是XML添加子菜单项,没有使用PopupMenu
(http://developer.android.com/guide/topics/ui/menus.html#PopupMenu)?
更新(解决方案):
我最后的代码片段最后是根据adamp的回复动态填充子菜单:
// menu options
private static final int MENU_PREFERENCES = Menu.FIRST;
private static final int MENU_LOGOUT = 2;
@Override
public boolean onCreateOptionsMenu(final Menu menu) {
super.onCreateOptionsMenu(menu);
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.main_menu, menu);
menu.add(0, MENU_PREFERENCES, 0, getString(R.string.general_preferences)).setIcon(
android.R.drawable.ic_menu_preferences);
// load all available form templates
Cursor c = managedQuery(FormsProviderAPI.FormsColumns.CONTENT_URI, null, null, null, null);
try {
int ixDisplayName = c.getColumnIndex(FormsProviderAPI.FormsColumns.DISPLAY_NAME);
int ixId = c.getColumnIndex(FormsProviderAPI.FormsColumns._ID);
int cnt = 0;
while (c.moveToNext()) {
cnt++;
Log.d("ID: ", "ID: "+ c.getInt(ixId)); // misusing the group id for the form id
menu.getItem(1).getSubMenu().addSubMenu(c.getInt(ixId), Menu.NONE, cnt, c.getString(ixDisplayName)).setIcon(R.drawable.attachment_dark);
}
} catch (Exception e) {
Log.e(TAG, "Error init form templates list.", e);
}
return true;
}
答案 0 :(得分:35)
是的,有。
addSubMenu
方法返回SubMenu
个对象。 SubMenu
也是Menu
,因此您可以在其上调用add
将项目添加到子菜单而不是父菜单。您上面的代码为表单1和表单2创建了两个不同的子菜单,而不是在单个“新建表单”子菜单中创建了两个项目。
示例:
SubMenu submenu = menu.addSubMenu(0, Menu.NONE, 1, "New Form").setIcon(R.drawable.ic_new_form);
submenu.add("Form 1").setIcon(R.drawable.attachment);
答案 1 :(得分:2)
添加ActionProvider可能更容易。您可以按照here
的说明进行尝试答案 2 :(得分:1)
您应该考虑使用ActionProvider
示例:https://gist.github.com/sibelius/7ca0b757492ff6740dec
带有操作提供商项目的菜单
<menu xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools">
<item android:id="@+id/action_companies"
android:icon="@drawable/ic_list"
android:title="@string/action_companies"
app:actionProviderClass="com.example.MyActionProvider"
app:showAsAction="always"/>
</menu>
代码
public class MyActionProvider extends ActionProvider {
private Context mContext;
public MyActionProvider(Context context) {
super(context);
mContext = context;
}
@Override
public View onCreateActionView() {
//LayoutInflater layoutInflater = LayoutInflater.from(mContext);
return null;
}
@Override
public void onPrepareSubMenu(SubMenu subMenu) {
super.onPrepareSubMenu(subMenu);
subMenu.clear();
subMenu.add("menu 1");
subMenu.add("menu 2");
subMenu.add("menu 3");
}
@Override
public boolean hasSubMenu() {
return true;
}
@Override
public boolean onPerformDefaultAction() {
return super.onPerformDefaultAction();
}
}