Question

我希望kwargs在method2中具有与传递给method1的内容完全相同的内容。在这种情况下，“foo”被传递给method1，但我想传入任意值，并在method1和method2中的kwargs中查看它们。对于我如何调用method2，我需要做些什么？

def method1(*args,**kwargs):

    if "foo" in kwargs:
        print("method1 has foo in kwargs")

    # I need to do something different here
    method2(kwargs=kwargs)

def method2(*args,**kwargs):

    if "foo" in kwargs:
        # I want this to be true
        print("method2 has foo in kwargs")

method1(foo=10)

输出：

method1 has foo in kwargs

期望的输出：

method1 has foo in kwargs
method2 has foo in kwargs

如果我需要澄清我在问什么，或者这是不可能的，请告诉我。

Answer 1

Keyword expansion.

method2(**kwargs)

Answer 2

def method1(*args,**kwargs):
    if "foo" in kwargs:
        print("method1 has foo in kwargs")

    method2(**kwargs)

Answer 3

它被称为解包参数列表。 python.org doc是here。在您的示例中，您将像这样实现它。

def method1(*args,**kwargs):      
    if "foo" in kwargs:         
        print("method1 has foo in kwargs")      

    # I need to do something different here     
    method2(**kwargs) #Notice the **kwargs.  

def method2(*args,**kwargs):      
    if "foo" in kwargs:         # I want this to be true         
        print("method2 has foo in kwargs")  

method1(foo=10)

方法1可以将kwargs传递给方法2吗？

3 个答案: