SocialEngine4:如何使用sql查询获取用户的性别?
答案 0 :(得分:2)
$subject = Engine_Api::_()->core()->getSubject(); //Get user
$fields = $subject->fields()->getFieldsValuesByAlias();
$gender = $fields['gender'];
$this->view->gender = $gender;
答案 1 :(得分:1)
使用下面列出的代码:
<?php
$currentUserID=Engine_Api::_()->user()->getViewer()->getIdentity();
$sSqlInviter="select gender from engine4_user_fields_search where item_id=".$currentUserID;
$dbInviterSqli=Zend_Db_Table_Abstract::getDefaultAdapter();
$stmtInviter=$dbInviterSqli->query($sSqlInviter);
$rowInviter=$stmtInviter->fetch();
$gender=$rowInviter['gender'];
if($gender==2)
echo "<b> Male</b>";
else
echo "<b> Female</b>";
?>
答案 2 :(得分:1)
$viewer = Engine_Api::_()->user()->getViewer();
$fields = Engine_Api::_()->fields()->getFieldsValuesByAlias($viewer);
echo $fields['gender'];
答案 3 :(得分:0)
您使用的是默认个人资料问题吗?然后:
From engine4_ser_fields_option
特定字段有和选项ID。