我有一个我要序列化的课程:
[XmlRoot(ElementName = "FileInfoMessage")]
public class Message : IMessage
{
[XmlAttribute]
public int Id { get; set; }
[XmlAttribute(Namespace = "Files")]
public Version { get; set; }
//...
}
和我的序列化方法:
//_xmlData - string containing xml content
public void SerializeData(IMessage message, Encoding encoding)
{
using (var stream = new MemoryStream())
{
var writerSettings = new XmlWriterSettings {Encoding = encoding, OmitXmlDeclaration = false, Indent = true, NamespaceHandling = NamespaceHandling.Default };
var writer = XmlWriter.Create(stream, writerSettings);
var serializer = new XmlSerializer(message.GetType());
var namespaces = new XmlSerializerNamespaces();
namespaces.Add("", "Files"); //if I add custom prefix, it will be visible
serializer.Serialize(writer, message, namespaces);
stream.Position = 0;
_xmlData = new StreamReader(stream).ReadToEnd();
}
我想要的是:
<?xml version="1.0" encoding="windows-1250"?>
<FileInfoMessage Id = "1" **xmlns="Files"** Version="2">
//...
</FileInfoMessage>
但我明白了:
<?xml version="1.0" encoding="windows-1250"?>
<FileInfoMessage Id = "1" p1:Version="2" xmlns:p1="Files">
//...
</FileInfoMessage>
如果我改变我的SerilizeMethod行: namespaces.Add(“whateverIwant”,“Files”);
我得到了: <?xml version="1.0" encoding="windows-1250"?>
<FileInfoMessage Id = "1" **xmlns:whateverIwant="Files"** Version="2">
//...
</FileInfoMessage>
任何可能的方法来实现它?
*经过一些修改后编辑。
答案 0 :(得分:0)
尝试将第一个参数的空字符串传递给namespaces.Add(“”,“Files”。据我所知,这就是诀窍。