我正在为我编写的局域网方网站构建一个插件,允许使用Round Robin锦标赛。
一切进展顺利,但我对排名超过两个标准的最有效方法有一些疑问。
基本上,我想要以下排名布局:
Rank Wins TotalScore
PersonE 1 5 50
PersonD 2 3.5 37
PersonA 2 3.5 37
PersonC 4 2.5 26
PersonB 5 2.5 24
PersonF 6 0 12
在SQL server中,我会使用:
SELECT
[Person],
RANK() OVER (ORDER BY Wins DESC, TotalScore DESC) [Rank],
[Wins],
[TotalScore]
现在,我只有List,Dictionary等可以使用
具体做法是:
Dictionary<TournamentTeam, double> wins = new Dictionary<TournamentTeam, double>();
Dictionary<TournamentTeam, double> score = new Dictionary<TournamentTeam, double>();
有没有办法用LINQ做这种排名方式?
如果没有,是否有可扩展的方式,以后我可以考虑Win-Loss-Draw而不是仅仅因为我选择获胜而获胜?
修改
我改编了TheSoftwareJedi的回答:
private class RRWinRecord : IComparable
{
public int Wins { get; set; }
public int Losses { get; set; }
public int Draws { get; set; }
public double OverallScore { get; set; }
public double WinRecord
{
get
{
return this.Wins * 1.0 + this.Draws * 0.5 + this.Losses * 0.0;
}
}
public int CompareTo(object obj) { ... }
public override bool Equals(object obj) { ... }
public override int GetHashCode() { ... }
public static bool operator ==(RRWinRecord lhs, RRWinRecord rhs) { ... }
public static bool operator !=(RRWinRecord lhs, RRWinRecord rhs) { ... }
public static bool operator >(RRWinRecord lhs, RRWinRecord rhs) { ... }
public static bool operator <(RRWinRecord lhs, RRWinRecord rhs) { ... }
public static bool operator >=(RRWinRecord lhs, RRWinRecord rhs) { ... }
public static bool operator <=(RRWinRecord lhs, RRWinRecord rhs) { ... }
}
...
int r = 1, lastRank = 1;
RRWinRecord lastRecord = null;
var ranks = from team in records.Keys
let teamRecord = records[team]
orderby teamRecord descending
select new RRRank() { Team = team, Rank = r++, Record = teamRecord };
foreach (var rank in ranks)
{
if (rank.Record != null && lastRecord == rank.Record)
{
rank.Rank = lastRank;
}
lastRecord = rank.Record;
lastRank = rank.Rank;
string scoreDescription = String.Format("{0}-{1}-{2}", rank.Record.Wins, rank.Record.Losses, rank.Record.Draws);
yield return new TournamentRanking(rank.Team, rank.Rank, scoreDescription);
}
yield break;
答案 0 :(得分:12)
排名并不太难。只需将OrderBy和Select实现模式混合在一起,您就可以使用一种易于使用的排名扩展方法。像这样:
public static IEnumerable<U> Rank<T, TKey, U>
(
this IEnumerable<T> source,
Func<T, TKey> keySelector,
Func<T, int, U> selector
)
{
if (!source.Any())
{
yield break;
}
int itemCount = 0;
T[] ordered = source.OrderBy(keySelector).ToArray();
TKey previous = keySelector(ordered[0]);
int rank = 1;
foreach (T t in ordered)
{
itemCount += 1;
TKey current = keySelector(t);
if (!current.Equals(previous))
{
rank = itemCount;
}
yield return selector(t, rank);
previous = current;
}
}
这是一些测试代码
string[] myNames = new string[]
{ "Bob", "Mark", "John", "Jim", "Lisa", "Dave" };
//
var query = myNames.Rank(s => s.Length, (s, r) => new { s, r });
//
foreach (var x in query)
{
Console.WriteLine("{0} {1}", x.r, x.s);
}
产生这些结果:
1 Bob
1 Jim
3 Mark
3 John
3 Lisa
3 Dave
答案 1 :(得分:3)
假设您有一个List<Result>
结构,其中Result
对象具有以下参数...
Pesron - string
Rank - int
Wins - double
TotalScore - int
您可以编写自定义比较器,然后将其传递给List.Sort(Comparison<Result> comparison)
替代方案,您可以将Result
对象实现IComparable<Result>
并坚持在你的班上。
#region IComparable Members
public int CompareTo(Result obj)
{
if (this.Rank.CompareTo(obj.Rank) != 0)
return this.Rank.CompareTo(obj.Rank);
if (this.Wins.CompareTo(obj.Wins) != 0)
return (this.Wins.CompareTo(obj.Wins);
return (this.TotalScore.CompareTo(obj.TotalScore) ;
}
#endregion
然后你可以拨打List<Result>.Sort()
;
答案 2 :(得分:2)
这适用于非密集级别:
static class Program
{
static IEnumerable<Result> GetResults(Dictionary<TournamentTeam, double> wins, Dictionary<TournamentTeam, double> scores)
{
int r = 1;
double lastWin = -1;
double lastScore = -1;
int lastRank = 1;
foreach (var rank in from name in wins.Keys
let score = scores[name]
let win = wins[name]
orderby win descending, score descending
select new Result { Name = name, Rank = r++, Score = score, Win = win })
{
if (lastWin == rank.Win && lastScore == rank.Score)
{
rank.Rank = lastRank;
}
lastWin = rank.Win;
lastScore = rank.Score;
lastRank = rank.Rank;
yield return rank;
}
}
}
class Result
{
public TournamentTeam Name;
public int Rank;
public double Score;
public double Win;
}
答案 3 :(得分:1)
这可能是一个开始:
Dictionary<TournamentTeam, double> wins = new Dictionary<TournamentTeam, double>();
Dictionary<TournamentTeam, double> score = new Dictionary<TournamentTeam, double>();
Dictionary<TournamentTeam, int> ranks = new Dictionary<TournamentTeam, int>();
int r = 1;
ranks = (
from name
in wins.Keys
orderby wins[name] descending, scores[name] descending
select new { Name = name, Rank = r++ })
.ToDictionary(item => item.Name, item => item.Rank);
答案 4 :(得分:1)
我意识到我已经迟到了,但无论如何我想拍摄。
这是一个仅使用LINQ的版本:
private IEnumerable<TeamRank> GetRankings(Dictionary<TournamentTeam, double> wins, Dictionary<TournamentTeam, double> scores)
{
var overallRank = 1;
return
from team in wins.Keys
group team by new { Wins = wins[team], TotalScore = scores[team] } into rankGroup
orderby rankGroup.Key.Wins descending, rankGroup.Key.TotalScore descending
let currentRank = overallRank++
from team in rankGroup
select new TeamRank(team, currentRank, rankGroup.Key.Wins, rankGroup.Key.TotalScore);
}
返回类型:
public class TeamRank
{
public TeamRank(TournamentTeam team, int rank, double wins, double totalScore)
{
this.Team = team;
this.Rank = rank;
this.Wins = wins;
this.TotalScore = totalScore;
}
public TournamentTeam Team { get; private set; }
public int Rank { get; private set; }
public double Wins { get; private set; }
public double TotalScore { get; private set; }
}