我有一个用JavaScript编写的弹出按钮。当用户单击该按钮时,它会打开一个PHP弹出窗口。点击时,我想通过GET或POST方法将值传递给该PHP页面,这是我弹出按钮的代码:
<form input type="BUTTON" value="popup button" onClick="javascript:popup('actionpage.php')">
</form>
<SCRIPT LANGUAGE="JavaScript">
function popup(URL) {
day = new Date();
id = day.getTime();
eval("page" + id + " = window.open(URL, '" + id + "', 'toolbar=0,scrollbars=0,location=0,statusbar=0,menubar=0,resizable=0,width=880,height=300');");
}
</script>
这里我想在用户点击“弹出按钮”时将值传递给actionpage.php。谢谢和问候,
答案 0 :(得分:1)
onClick="javascript:popup('actionpage.php?foo=bar')"
答案 1 :(得分:0)
您可以在查询字符串上传递参数,并在PHP页面中处理服务器端。
另请注意,eval()
的使用是不必要的,并且通常不赞成您的FORM/INPUT
标记格式错误。我相信我已经在下面的例子中对其进行了更正。
<form>
<input type="button" value="popup button" onclick="popup('actionpage.php')" />
</form>
<script>
function popup(URL) {
var day = new Date();
var id = day.getTime();
window.open(
URL + "?id=" + id,
'toolbar=0,
scrollbars=0,
location=0,
statusbar=0,
menubar=0,
resizable=0,
width=880,
height=300'
);
}
</script>
答案 2 :(得分:0)
您可以使用以下代码发送数据:
var http = new XMLHttpRequest();
http.open("POST", 'path/to/php', true);
http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http.setRequestHeader("Content-length", params.length);
http.setRequestHeader("Connection", "close");
http.send(params);
答案 3 :(得分:0)
function popup(URL) {
day = new Date();
**URL=URL+"?foo=bar&foo2=bar2";**
id = day.getTime();
eval("page" + id + " = window.open(URL, '" + id + "', 'toolbar=0,scrollbars=0,location=0,statusbar=0,menubar=0,resizable=0,width=880,height=300');");
}
答案 4 :(得分:0)
希望这会对你有所帮助。
<form>
<input type="BUTTON" value="popup button" onClick="javascript:popup('array.php')">
</form>
<SCRIPT LANGUAGE="JavaScript">
function popup(URL) {
day = new Date();
id = day.getTime();
eval("page" + id + " = window.open(URL + '?id=' + id , '" + id + "', 'toolbar=0,scrollbars=0,location=0,statusbar=0,menubar=0,resizable=0,width=880,height=300');");
}
</script>
在PHP页面中,只需使用$_GET['id']
即可获取ID。
<?php
$id = $_GET['id'];
?>