所有
我正在努力创造一个'到&来自'动画使用jquery animate& css转换属性。
我提到了this关于在动画中使用步长函数的帖子,但是,我没有取得多大成功。请检讨&建议。
HTML:
<ul id="a">
<li class="cAccessories" id="AccButtons"><span>blah blah..</span></li>
<li class="cAccessories" id="AccRibbons"><span>blah blah..</span></li>
<li class="cAccessories" id="AccLaces"><span>blah blah..</span></li>
<li class="cAccessories" id="AccEmbroider"><span>blah blah..</span></li>
</ul>
CSS:
#a {
position: absolute;
top: 25px;
left: 25px;
width: 150px;
height: 150px;
padding: 0;
margin: 0;
list-style: none;
background-color: blue;
}
JAVASCRIPT:
$("#a").animate ({"margin-left": "+=10px"}, {step: function (now, fx) {
$("#a").css ("-moz-transform", "rotate('5deg')");
$("#a").css ("-webkit-transform", "rotate ('5deg')");
$("#a").css ("-ms-transform", "rotate ('5deg')");
$("#a").css ("-o-transform", "rotate ('5deg')");
}, duration: "slow"}, "linear", function ()
{
$("#a").animate ({left: "+=0px"}, {step: function (now, fx) {
$("#a").css ("-webkit-transform", "rotate ('-5deg')");
$("#a").css ("-moz-transform", "rotate ('-5deg')");
$("#a").css ("-ms-transform", "rotate ('-5deg')");
$("#a").css ("-o-transform", "rotate ('-5deg')");
}, duration: "slow"}, "linear" ); });
以下是原始代码,我不喜欢变换动画(尽管它完美地动画了'top'值)。
iTemplateNo = $(this).attr("id").substr (-1, 1);
eCurHanger = document.getElementById("hanger0" + iTemplateNo);
$(eCurHanger).attr("src", "Img/V2/Hanger.png");
$(eCurHanger).css ({"width": "45px", "height": "35px"});
$(eCurHanger).animate ({top: "+=10px"}, {step: function (angle, fx) {
$(eCurHanger).css ({"-webkit-transform": "rotate ("+angle+"deg)",
"-moz-transform": "rotate ("+angle+"deg)",
"-ms-transform": "rotate ("+angle+"deg)",
"-o-transform": "rotate ("+angle+"deg)"});
}, duration: 1000}, "linear", function ()
{
$(eCurHanger).animate ({left: "+=10px"}, {step: function (angle, fx) {
$(this).css ({"-webkit-transform": "rotate("+angle+"deg)",
"-moz-transform": "rotate("+angle+"deg)",
"-ms-transform": "rotate("+angle+"deg)",
"-o-transform": "rotate("+angle+"deg)"})
}, duration: 1000}, "linear" ) });
答案 0 :(得分:2)
我不知道eCurHanger
是什么,但请看http://jsfiddle.net/8tP9D/
var angle = 0;
$("#a").animate ({"margin-left": "+=200px"}, {step: function (now, fx) {
angle += 1;
$(this).css ({"-moz-transform":"rotate("+angle+"deg)",
"-webkit-transform":"rotate("+angle+"deg)",
"-ms-transform":"rotate("+angle+"deg)",
"-o-transform":"rotate("+angle+"deg)"});
}, duration: 5000}, "linear");
而不是全局angle
您可以使用now
变量。 http://jsfiddle.net/39pe6/
$("#a").animate ({"margin-left": "+=200px"}, {step: function (angle, fx) {
$(this).css ({"-moz-transform":"rotate("+angle+"deg)",
"-webkit-transform":"rotate("+angle+"deg)",
"-ms-transform":"rotate("+angle+"deg)",
"-o-transform":"rotate("+angle+"deg)"});
}, duration: 5000}, "linear");
答案 1 :(得分:1)
研究了一下。有一些语法错误。以下是您需要的输出我认为Click Here!。
与我合作的代码在这里:
$("#a").animate({ textIndent: 5 }, {
step: function(now,fx)
{
$(this).css({
'-webkit-transform':'rotate('+now+'deg)',
'transform':'rotate('+now+'deg)',
'-ms-transform':'rotate('+now+'deg)'});
},duration:1000,
complete:function() {
$("#a").animate({ textIndent: -5 }, {
step: function(now,fx)
{
$(this).css({
'-webkit-transform':'rotate('+now+'deg)',
'transform':'rotate('+now+'deg)',
'-ms-transform':'rotate('+now+'deg)'});
},duration:1000
});
}});