PHP中的日期MySQL查询

Question

如何在PHP中更改此MySQL查询，以仅显示数据库中名为OpenHouseDate的日期列为当前日期或前方的所有列表？

$sql_query = "SELECT * FROM listings ORDER BY RAND()";

Answer 1

$sql_query = "SELECT * FROM listings where OpenHouseDate >= current_date ORDER BY RAND()";

Answer 2

SELECT * FROM listings WHERE DATE(OpenHouseDate) = DATE(NOW()) ORDER BY RAND()

Answer 3

如果OpenHouseDate属于“日期”类型，则可以使用以下内容：

$sql_query = "SELECT * FROM listings WHERE OpenHouseDate <= CURDATE();

如果OpenHouseDate属于'DateTime'类型，那么您可以使用以下内容：

$sql_query = "SELECT * FROM listings WHERE OpenHouseDate <= NOW();

如果OpenHouseDate属于'Integer'类型，那么您可以使用以下内容：

$sql_query = "SELECT * FROM listings WHERE OpenHouseDate <= UNIX_TIMESTAMP(NOW());

MySQL Date/Time Reference