Question

如何呈现特定次数？我正在制作我的topmenu和sidemenu有相同的页面。我希望topmenu只显示前4页，并且sidemenu显示所有可用的页面。

<%= render :partial => '/shared/menu_branch', :collection => roots, :locals => {

           :hide_children => hide_children,
           :sibling_count => (roots.length - 1),
           :apply_css => true 
} -%>

和menu_branch

<%
  if !!local_assigns[:apply_css] and (classes = menu_branch_css(local_assigns)).any?
    css = "class='#{classes.join(' ')}'".html_safe
  end
  dom_id = "id='item_#{menu_branch_counter}'".html_safe if menu_branch.parent_id.nil?
-%>

<li<%= ['', css, dom_id].compact.join(' ').gsub(/\ *$/, '').html_safe %>>
  <%= link_to menu_branch.title, menu_branch.url -%>
</li>

这是我想要渲染4次的线。

<li<%= ['', css, dom_id].compact.join(' ').gsub(/\ *$/, '').html_safe %>>
  <%= link_to menu_branch.title, menu_branch.url -%>
</li>

Answer 1

好吧，我自己想通了。这是我改变的代码。

 <%= render :partial => '/shared/menu_branch', :collection => roots.select{|p|roots.rindex(p) < 4}, :locals => {
                 :hide_children => hide_children,
                 :sibling_count => (roots.length - 1),
                 :apply_css => true 
               } -%>

这是我添加的内容。

:collection => roots.select{|p|roots.rindex(p) < 4},

如何呈现特定次数？

1 个答案: