Question

就我而言，我有一个soap响应，其中存储了一个“ArrayOfArrayOfString”类型的值。

它就像一个数组 A [4] [4] 。

A [0] [0] - ＆gt; SERVICEID

A [0] [1] - ＆gt;服务名称

A [0] [2] - ＆gt; ServiceImageURL

A [0] [3] - ＆gt; ServiceDecription

A [0] [4] - ＆gt; ServiceIconURL

和A [4] [4]一样。

如何在android中处理这种类型的响应？

代码类似于：

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);        

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        envelope.dotNet = true;

        envelope.setOutputSoapObject(request);

        HttpTransportSE transportSE = new HttpTransportSE(URL);
        transportSE.debug = true;

                                            Log.i("WebService", "msg:try_out");
    String[] columns = null;

    ArrayList<String> rows = new ArrayList<String>();

    try
    {
                                                    Log.i("WebService", "msg:try+in");
        transportSE.call(SOAP_ACTION, envelope);                            
                                                    Log.i("WebService", "msg:SoapObject");


        SoapObject response = (SoapObject)envelope.getResponse();           

                                                    Log.i("WebService", "Response");

try
            {
                // WhaT SHOULD I USE HERE to convert it to 2D Array//
            }
            catch (Exception e)
            {
                e.printStackTrace();
                Log.v("CATCH BLOCK", e.getMessage());
            }
}
        catch (Exception e) 
        {
            e.printStackTrace();
            Log.i("WebService", "msg:Exception error");
            Log.i("WebSerivce", e.getMessage());
            return e.getMessage();
        }

请帮我解决这个问题。

Answer 1

这是解析复杂数据的完美工作代码......

我只是为A [0] [1-4]做这个，根据我的肥皂反应根据你的肥皂反应修改代码。

SoapObject result = (SoapObject)enevlop.getResponse();

            String str = result.getProperty(0).toString();
            // add a for loop for ur code and iterate it according to ur soap response and get all the node using getProperty(i);

            String str1 = lameParser(str);

            textView.setText(""+str1);

现在定义lameParser（）方法： -

    public String lameParser(String input){

    String sName=input.substring(input.indexOf("sName=")+6, input.indexOf(";", input.indexOf("sName=")));

    int IGoals=Integer.valueOf(input.substring(input.indexOf("iGoals=")+7, input.indexOf(";", input.indexOf("iGoals="))));

    String sCountry=input.substring(input.indexOf("sCountry=")+9, input.indexOf(";", input.indexOf("sCountry=")));

    String sFlag=input.substring(input.indexOf("sFlag=")+6, input.indexOf(";", input.indexOf("sFlag=")));

    return sName+"\n"+Integer.toString(IGoals)+"\n"+sCountry+"\n"+sFlag;
 }

Answer 2

这是解析xml数据的多个子节点的代码......

public static void parseBusinessObject(String input, Object output) throws NumberFormatException, IllegalArgumentException, IllegalAccessException, InstantiationException{

        Class theClass = output.getClass();
        Field[] fields = theClass.getDeclaredFields();

        for (int i = 0; i < fields.length; i++) {
            Type type=fields[i].getType();
            fields[i].setAccessible(true);

            //detect String
            if (fields[i].getType().equals(String.class)) {
                String tag = "s" + fields[i].getName() + "=";   //"s" is for String in the above soap response example + field name for example Name = "sName"
                if(input.contains(tag)){
                    String strValue = input.substring(input.indexOf(tag)+tag.length(), input.indexOf(";", input.indexOf(tag)));
                    if(strValue.length()!=0){
                        fields[i].set(output, strValue);
                    }
                }
            }

            //detect int or Integer
            if (type.equals(Integer.TYPE) || type.equals(Integer.class)) {
                String tag = "i" + fields[i].getName() + "=";  //"i" is for Integer or int in the above soap response example+ field name for example Goals = "iGoals"
                if(input.contains(tag)){
                    String strValue = input.substring(input.indexOf(tag)+tag.length(), input.indexOf(";", input.indexOf(tag)));
                    if(strValue.length()!=0){
                        fields[i].setInt(output, Integer.valueOf(strValue));
                    }
                }
            }

            //detect float or Float
            if (type.equals(Float.TYPE) || type.equals(Float.class)) {
                String tag = "f" + fields[i].getName() + "=";
                if(input.contains(tag)){
                    String strValue = input.substring(input.indexOf(tag)+tag.length(), input.indexOf(";", input.indexOf(tag)));
                    if(strValue.length()!=0){
                        fields[i].setFloat(output, Float.valueOf(strValue));
                    }
                }
            }
        }

    }

如果您希望帖子给我投票，以便访问者轻松找到它......

Answer 3

try
{
      Log.i("WebService", "Try Block");
      transportSE.call(SOAP_ACTION, envelope);                          
      Log.i("WebService", "msg:SoapObject");

      SoapObject response = (SoapObject)envelope.getResponse();
      Log.i("WebService", "Response on");
      int totalService = response.getPropertyCount();

      int i;
      String str ;
      String str1;

      for (i = 0; i < totalService; i++)
         {
        str = response.getProperty(i).toString();
            Log.i("WebService", "ForLoop "+ Integer.toString(i));
        str1 = lameParser(str, i);
            Log.i("WebService", "ForLoop: lameParser done");
            Log.i("WebService", "Value Stored:: "+ str1);
        }
        }                                               
        catch (Exception e) 
        {
            e.printStackTrace();
            Log.i("WebService", "msg:Exception error");
            Log.i("WebSerivce", e.getMessage());

        }                   

    }



    private String lameParser(String input, int I)
    {
       int i = I;
       Log.i("WebService", "LameParse()" );
    try
    {
    String SId = input.substring(input.indexOf("{string=")+8, input.indexOf(";", input.indexOf("{string=")));
        String SName = input.substring(input.indexOf(" string=")+8, input.indexOf(";", input.indexOf(" string=")));
        String SIurl = input.substring(input.indexOf("http"), input.indexOf(";", input.indexOf("http")));
        String SIcon = input.substring(input.indexOf("jpg; string=")+12, input.indexOf("; }", input.indexOf("jpg; string=")));

        // String[][] arr = new String[x][y]; is already initialized as local var of class.
        arr[i][0] = SId;
        arr[i][1] = SName;
        arr[i][2] = SIurl;
        arr[i][3] = SIcon;



        return SId + "\n" + SName + "\n" + SIurl +  "\n" +  SIcon + "\n" ;

        }
        catch (Exception e)
        {
            Log.i("WebService", "catch exception" );
            Log.i("WebService", e.getMessage());
            return null;
        }
    }

Answer 4

以下是我处理ArrayOfArrayOfString对象的方法。

SoapObject result = (SoapObject)envelope.bodyIn;
if (result.getPropertyCount() > 0) {
    SoapObject Rows = (SoapObject)result.getProperty(0);
    int nRows = Rows.getPropertyCount();
    for (int nRow=0; nRow<nRows; nRow++) {
        SoapObject Cols = (SoapObject)Rows.getProperty(nRow);
        int nCols = Cols.getPropertyCount();
        for (int nCol=0; nCol<nCols; nCol++) {
            String sCol = Cols.getProperty(nCol).toString();

            // Process sCol with nRow and nCol as array indexes
        }
    }
}

如何将Soap响应转换为多维数组？

4 个答案: