Question

我想用JSONPath解析它：

[
  [50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
  [50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
]

请帮忙吗？

Answer 1

如果对象是：

[
  [50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
  [50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
]

然后"$[0]"将返回：

[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]

"$[1]"将返回：

[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]

你也可以做两级深度。 "$[0][4]"将返回：

您还可以使用"$[*]"将数组元素提取到列表中，该列表将返回2个元素的列表。第一个是：

[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]

，第二个是：

[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]

Answer 2

使用DefiantJS，您可以使用XPath语法搜索JSON结构。该库使用搜索功能扩展了全局对象JSON。

在这种情况下，你可以写这样的东西;

var data = [
  [50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
  [50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
],
search = JSON.search( data, '//*/*/*' );

看看这个小提琴; http://jsfiddle.net/hbi99/5NfeM/

Answer 3

这对我有用

JsonPath.with(jsonResponse).param("name", "getName").get("findAll { a -> a.name == name  }")

使用JSONPATH解析JSON数组文件

3 个答案: