Question

如果你有这个：

foreach(string n in txtList)
{
    Console.WriteLine(n);
}

输出：

[HKEY_Something_Something\.abc]
[HKEY_Something_Something\.defg]
[HKEY_Something_Something\.ijklmn]

我如何得到“。”之间的内容。和“]”？

Answer 1

如果它始终遵循该格式，将代码更改为此应输出您想要的内容：

foreach(string n in txtList)
{
  int startindex = n.IndexOf(@"\.") + 2;
  Console.WriteLine(n.Substring( startindex, n.Length-startindex-1));
}

Answer 2

尝试

 foreach(string n in txtList)
    {
        string str[] = n.Split('.');
        if (str.Length > 0)
        {
            string s = str[str.Length-1];
            Console.WriteLine(s.Substring(0, s.Length-1));
        }
    }

Answer 3

您可以使用正则表达式：

var s = @"[HKEY_Something_Something\.abc]";
var result = Regex.Match(s, @"(?<=\.)[^]]*(?=]$)")
// result == "abc"

正则表达式的简短说明：

(?<=\.) - preceded by a dot
[^]]*   - anything which isn't a ']'
(?=]$)  - followed by a ']' and the end of the string

Answer 4

var per = n.IndexOf("."); // may need to add +1 to get past . index.
var len = n.IndexOf("]") - per - 1;

var val = n.Substring(per, len);

Answer 5

简单回答：

int dotPosition = n.LastIndexOf(".") + 1; // +1 because we start AFTER the dot.
int bracketPosition = n.LastIndexOf("]"); // can do "n.Length - 2" too.
Console.WriteLine(n.Substring(dotPosition, bracketPosition - dotPosition));

更复杂的答案：使用正则表达式。

Answer 6

例如使用RegEx：

  Match match = Regex.Match(n, @"\.(.*)\]");  
  string result = match.Groups[1].Value;

读取字符串中的字符串

6 个答案: