我在Spring JPA中遇到了一些问题。我成功配置了Spring JPA项目,并且能够毫无例外地运行项目。
我打算将实体保存到数据库中。但是当我运行项目时,它既没有保存到数据库也没有抛出任何异常。
可能是什么问题?我添加了许多与hiberate相关的jar文件,因为它在我运行时抛出异常。现在我没有任何例外。但实体不会保存到数据库中。我已经附加了我的Spring配置和Java类。
sprig配置
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:osgi="http://www.springframework.org/schema/osgi"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/osgi
http://www.springframework.org/schema/osgi/spring-osgi.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd">
<context:property-placeholder location="classpath:jdbc.properties"/>
<!-- Connection Pool -->
<bean id="dataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource" destroy-method="close">
<property name="driverClass" value="${jdbc.driverClass}"/>
<property name="jdbcUrl" value="${jdbc.url}"/>
<property name="user" value="${jdbc.username}"/>
<property name="password" value="${jdbc.password}"/>
</bean>
<!-- JPA EntityManagerFactory -->
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:dataSource-ref="dataSource">
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="database" value="${jdbc.database}"/>
<property name="showSql" value="${jdbc.showSql}"/>
</bean>
</property>
</bean>
<!-- Transaction manager for a single JPA EntityManagerFactory (alternative to JTA) -->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
p:entityManagerFactory-ref="entityManagerFactory"/>
<!-- Activates various annotations to be detected in bean classes for eg @Autowired-->
<context:annotation-config/>
<!-- enable the configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="transactionManager"/>
<!-- <context:component-scan base-package="com.vemanchery.timesheet.dao"/> -->
<!-- Implementation Class -->
<bean id="employeeDao" class="com.test.dao.impl.EmployeeDao" />
<!-- services -->
<bean id="employeeService" class="com.test.service.impl.EmployeeService" >
<property name="employeeDao" ref="employeeDao"/>
</bean>
</beans>
DAO
package com.test.dao.impl;
import java.util.List;
import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import javax.persistence.Query;
import com.test.dao.interfaces.IEmployeeDao;
import com.test.model.interfaces.IEmployee;
//@Repository
//@Component
public class EmployeeDao implements IEmployeeDao{
@PersistenceContext()
private EntityManager entityManager ;
@Override
public boolean createEmployee(IEmployee employee) {
this.entityManager.persist(employee);
return true;
}
}
服务层
package com.test.service.impl;
import org.springframework.beans.factory.annotation.Autowired;
import com.test.dao.impl.EmployeeDao;
import com.test.dao.interfaces.IEmployeeDao;
import com.test.model.interfaces.IEmployee;
import com.test.service.interfaces.IEmployeeService;
public class EmployeeService implements IEmployeeService{
@Autowired
IEmployeeDao employeeDao;
public IEmployeeDao getEmployeeDao() {
return employeeDao;
}
public void setEmployeeDao(IEmployeeDao employeeDao) {
this.employeeDao = employeeDao;
}
/**
*
*/
public boolean addEmployee(IEmployee employee){
employeeDao.createEmployee(employee);
return false;
}
}
答案 0 :(得分:2)
在服务类或存储实体的方法上添加@Transactional
注释:
@Transactional
public boolean addEmployee(IEmployee employee){
employeeDao.createEmployee(employee);
return false;
}
在你的DAO上添加@Repository
也是一个好主意,但它不会导致你的问题。
答案 1 :(得分:0)
为服务和dao启用基于注释的处理(我从未混合过xml配置和注释,因此不知道配置设置是否正常)并标记您的服务方法
addEmployee @Transactional
希望这有帮助