Question

Envrionment：Java，Hibernate JPA提供程序，JPA，Oracle DB

我正在尝试创建一个本机查询来从Oracle DB中获取数据。其中一列是日期列。提取日期，但时间戳显示为00:00:00。但是，通过SQL浏览器，我可以看到日期和时间。如何获取resultList以及时间？

org.hibernate.Query query = ((HibernateEntityManager) entityManager).getSession().
                                     createSQLQuery(NATIVE_QUERY).setResultTransformer(org.hibernate.transform.Transformers.ALIAS_TO_ENTITY_MAP);

query.setString(0, accountNumber);;
query.setTimestamp(1, startDate).setTimestamp(2, endTime);
query.setTimestamp(3, startDate).setTimestamp(4,endTime);
List resultList = query.list();

查询本身（在上面的代码中 - NATIVE_QUERY）是一个普通的SQL查询 - “获取给定日期范围内的所有用户名和txn时间，无论是新事务还是以某种形式更改的事物” 。

选择u.first_name作为firstName，u.last_name作为lastName，tx.start_time作为txnTime来自用户u，事务tx，其中tx.user_id = u.user_id和tx.account_number =？和（tx.start_time＆gt;？和tx.start_time＆lt;？或tx.change_time＆gt;？和tx.change_time＆lt;？）

for(Object listItem : resultList){
    Map map = (Map) listItem;
    Date txnTime = (Date)map.get("txnTime".toUpperCase()); 
   //--------> NOT FETCHING THE TIME. I get the time as 00:00:00
}

域模型非常简单

    @Entity
    @Table(name="TRANSACTION")
    @org.hibernate.annotations.Entity(
        dynamicUpdate = true
    )
    public class Transaction{
        @Id
        @SequenceGenerator(name="txn_gen", sequenceName="TXN_S")
        @GeneratedValue(generator="txn_gen")
        @Column(name="TXN_ID")
        private Long txnId;

        @ManyToOne(fetch=FetchType.LAZY)
        @JoinColumn(name="USER_ID", nullable=false)
        private User user;

        @Column(name="START_TIME", nullable=false)
        @Temporal(TemporalType.TIMESTAMP)
        private java.util.Date startTime;

        @Column(name="CHANGE_TIME")
        @Temporal(TemporalType.TIMESTAMP)
        private java.util.Date changeTime;
    }

@Entity
@Table(name="USER")
@org.hibernate.annotations.Entity(
    dynamicUpdate = true
)
public class User {
    @Id
    @SequenceGenerator(name = "user_gen", sequenceName = "USER_S")
    @GeneratedValue(generator = "user_gen")
    @Column(name="USER_ID")
    private Long userId;    

    @Column(length=500, name="FIRST_NAME")
    private String firstName;

    @Column(length=500, name="LAST_NAME")
    private String lastName;
 }

Hibernate - createQuery不提取时间戳

0 个答案: