Question

如何解析JDBC URL（oracle或sqlserver）以获取主机名，端口和数据库名称。 URL的格式不同。

Answer 1

从这样的事情开始：

String url = "jdbc:derby://localhost:1527/netld;collation=TERRITORY_BASED:PRIMARY";
String cleanURI = url.substring(5);

URI uri = URI.create(cleanURI);
System.out.println(uri.getScheme());
System.out.println(uri.getHost());
System.out.println(uri.getPort());
System.out.println(uri.getPath());

以上输出：

derby
localhost
1527
/netld;collation=TERRITORY_BASED:PRIMARY

Answer 2

这对我没有用。我提出了这些方法，基于主机名和端口始终通过冒号连接在一起的假设。这个假设适用于我在工作中处理的所有数据库（Oracle，Vertica，MySQL等）。但它可能不适用于那些无法接触到网络端口的东西。

String url = null; // set elsewhere in the class
final public String regexForHostAndPort = "[.\\w]+:\\d+";
final public Pattern hostAndPortPattern = Pattern.compile(regexForHostAndPort);
public String getHostFromUrl() {
    Matcher matcher = hostAndPortPattern.matcher(url); 
    matcher.find();
    int start = matcher.start();
    int end = matcher.end();
    if(start >= 0 && end >= 0) {
        String hostAndPort = url.substring(start, end);
        String [] array = hostAndPort.split(":");
        if(array.length >= 2)
            return array[0];
    }
    throw new IllegalArgumentException("couldn't find pattern '" + regexForHostAndPort + "' in '" + url + "'");
}

public int getPortFromUrl() {
    Matcher matcher = hostAndPortPattern.matcher(url); 
    matcher.find();
    int start = matcher.start();
    int end = matcher.end();
    if(start >= 0 && end >= 0) {
        String hostAndPort = url.substring(start, end);
        String [] array = hostAndPort.split(":");
        if(array.length >= 2)
            return Integer.parseInt(array[1]);
    }
    throw new IllegalArgumentException("couldn't find pattern '" + regexForHostAndPort + "' in '" + url + "'");
}

Answer 3

我在我的项目中使用这个类。使用非常简单。

/**
 * Split di una url JDBC nei componenti.
 * Estrae i componenti di una uri JDBC del tipo: <br>
 * String url = "jdbc:derby://localhost:1527/netld;collation=TERRITORY_BASED:PRIMARY"; <br>
 * nelle rispettive variabili pubbliche.
 * @author Nicola De Nisco
 */
public class JdbcUrlSplitter
{
  public String driverName, host, port, database, params;

  public JdbcUrlSplitter(String jdbcUrl)
  {
    int pos, pos1, pos2;
    String connUri;

    if(jdbcUrl == null || !jdbcUrl.startsWith("jdbc:")
       || (pos1 = jdbcUrl.indexOf(':', 5)) == -1)
      throw new IllegalArgumentException("Invalid JDBC url.");

    driverName = jdbcUrl.substring(5, pos1);
    if((pos2 = jdbcUrl.indexOf(';', pos1)) == -1)
    {
      connUri = jdbcUrl.substring(pos1 + 1);
    }
    else
    {
      connUri = jdbcUrl.substring(pos1 + 1, pos2);
      params = jdbcUrl.substring(pos2 + 1);
    }

    if(connUri.startsWith("//"))
    {
      if((pos = connUri.indexOf('/', 2)) != -1)
      {
        host = connUri.substring(2, pos);
        database = connUri.substring(pos + 1);

        if((pos = host.indexOf(':')) != -1)
        {
          port = host.substring(pos + 1);
          host = host.substring(0, pos);
        }
      }
    }
    else
    {
      database = connUri;
    }
  }
}

Answer 4

请注意，对于某些有效的jdbc url，@ brettw的答案可能会失败。如果主机名包含下划线uri，则getHost（）返回null（请参见here），而getPost（）返回-1。

要解决此问题，我添加了一个空主机检查：

  String jdbcUrl = "jdbc:jtds:sqlserver://ABC_XYZ:1433/Database";
  String cleanURI = jdbcUrl.substring("jdbc:jtds:".length());

  URI uri = URI.create(cleanURI);
  String host = uri.getHost();
  int port = uri.getPort();

  if(host == null){
    String regex = ".*://(\\w*):(\\d++)/.*";
    Pattern p = Pattern.compile(regex);

    Matcher matcher = p.matcher(jdbcUrl);
    if(matcher.find()){
      host =  matcher.group(1);
      port =  Integer.valueOf(matcher.group(2));
    } else {
      // handle fail
    }
  }

  System.out.println("host = " + host);
  System.out.println("port = " + port);

如何解析JDBC url以获取主机名，端口等？

4 个答案: