我有两个excel电子表格,一个包含各种人的数据,而另一个则是一个索引。
'指数'电子表格如下(作为示例);
A B
1 [person:][pID: ]
2 [Mark ][1 ]
3 [James ][2 ]
4 [John ][3 ]
5 [David ][4 ]
n [ ... ][n ]
'数据'电子表格如下(作为示例);
A
1 [pID: ][ ...
2 [David ][ ...
3 [David ][ ...
4 [David ][ ...
5 [James ][ ...
6 [Mark ][ ...
7 [David ][ ...
n [ ... ][ ...
我想要做的是更换数据'中的A列。电子表格,以及“索引”的相应索引。电子表格,可能使用VBA。
结果将是这样的;
A
1 [pID: ][ ...
2 [4 ][ ...
3 [4 ][ ...
4 [4 ][ ...
5 [2 ][ ...
6 [1 ][ ...
7 [4 ][ ...
n [ ... ][ ...
我见过一些使用switch语句的静态方法,但我真的希望能够从另一个电子表格中导入数据。 我试图不去复制粘贴和“全部替换”。
谢谢!
答案 0 :(得分:4)
试试这个:
Sub HTH()
With Sheets("Data")
.Columns(2).Insert Shift:=xlToRight, CopyOrigin:=xlFormatFromLeftOrAbove
.Cells(1, "B").Value = .Cells(1, "A").Value
With .Range("A2", .Cells(Rows.Count, "A").End(xlUp)).Offset(, 1)
.Formula = "=VLOOKUP(A2,Index!A:B,2,FALSE)"
.Value = .Value
End With
.Columns(1).Delete
End With
End Sub
说明:
Sub HTH()
With Sheets("Data")
'// Insert a new column with same format
.Columns(2).Insert Shift:=xlToRight, CopyOrigin:=xlFormatFromLeftOrAbove
'// Copy the header
.Cells(1, "B").Value = .Cells(1, "A").Value
'// Work with the used range of column A
With .Range("A2", .Cells(Rows.Count, "A").End(xlUp)).Offset(, 1)
'// Use a formula to replace the names with corresponding values
.Formula = "=VLOOKUP(A2,Index!A:B,2,FALSE)"
'// Replace formula with value
.Value = .Value
End With
'// Delete the old column
.Columns(1).Delete
End With
End Sub
注意:强>
就个人而言,我会保留原始数据表,并使用一个演示文稿表查找数据表和索引表,并按照您的需要提供。那么你不一定需要代码,如果你仍然想要使用代码,那么代码将更加简单。您需要添加代码以关闭屏幕更新并使用错误处理等。
ja72解决方案的替代方案:
Sub HTH()
Dim vNames As Variant, vResult As Variant
Dim lLoop As Long
vNames = Sheets("Index").UsedRange.Columns(1).Resize(, 2).Value2
vResult = Sheets("Data").UsedRange.Columns(1).Value2
With CreateObject("Scripting.Dictionary")
For lLoop = 2 To UBound(vNames, 1)
.Add vNames(lLoop, 1), vNames(lLoop, 2)
Next lLoop
For lLoop = 2 To UBound(vResult, 1)
vResult(lLoop, 1) = .Item(vResult(lLoop, 1))
Next lLoop
Sheets("Data").Range("A1").Resize(UBound(vResult, 1), 1).Value = vResult
End With
End Sub
悄悄地确信它也更快;)
答案 1 :(得分:1)
尝试使用VBA:
Public Sub FindPID()
Dim i As Integer, N As Integer
Dim r_index As Range
' Find start of index
Set r_index = Sheets("Index").Range("A2")
' Count rows in index
N = r_index.Worksheet.Range(r_index, r_index.End(xlDown)).Rows.Count
' Expand range with all values
Set r_index = r_index.Resize(N, 2)
Dim vals As Variant
' Move values into array
vals = r_index.Value2
' Create a lookup collection
Dim lup As New Collection
For i = 1 To N
' Add each pID to collection with name as key
lup.Add vals(i, 2), vals(i, 1)
Next i
Dim r_data As Range, M As Integer
' Find start of data
Set r_data = Sheets("Data").Range("A2")
' Count rows in data
M = r_data.Worksheet.Range(r_data, r_data.End(xlDown)).Rows.Count
' Expand range with all values
Set r_data = r_data.Resize(M, 1)
' Move values into array
vals = r_data.Value2
For i = 1 To M
' Replace first column with lookup pID
vals(i, 1) = lup(vals(i, 1))
Next i
' Assign values from array back to cells.
r_data.Value2 = vals
End Sub
这将是最快的。
答案 2 :(得分:1)
我不相信VBA是这个问题的最佳解决方案。一个简单的VLOOKUP可以完全满足您的需求。
=VLOOKUP(Data!$A1, Index!$A$2:$A$5, 1, FALSE)
会为您提供您正在寻找的结果。