我创建了一个将数据插入SQL数据库的应用程序。基本上,从主窗体开始,用户打开第二个窗体,提示他们输入将进入数据库的数据。代码如下所示:
private void submitButton_Click(object sender, EventArgs e)
{
//Get form values
try
{
//Open test connection
}
catch (Exception ex)
{
//Handle errors
}
finally
{
//Close test connection
}
//Run the SQL statements
try
{
//Inser SQL data
}
catch (Exception ie)
{
//Handle errors
}
finally
{
//Close the connection
if (conn.State != ConnectionState.Closed)
{
//Close the connection
}
//Close the window
this.Close();
//Tell the main form to reload SQL data (not working)
mainForm firstForm;
firstForm = new mainForm();
firstForm.refreshCall();
}
}
}
基本上,当用户点击OK(submitButton)时,插入数据,关闭窗口,并调用refreshCall()
方法。我的方法'refreshCall
'应该刷新在主窗体上输出的SQL数据,如下所示:
public void refreshCall()
{
SqlConnection conn = new SqlConnection("Data Source=SERVER\\SQL_DB;Initial Catalog=dataTable;Integrated Security=True");
try
{
conn.Open();
DataSet ds = new DataSet();
SqlDataAdapter adapter = new SqlDataAdapter("SELECT part_num from dbo.Parts", conn);
adapter.Fill(ds);
this.listParts.DataSource = ds.Tables[0];
this.listParts.DisplayMember = "part_num";
conn.Close();
}
catch (SqlException odbcEx)
{
MessageBox.Show("There was an error connecting to the data source.\nError Code: 1001", "Database Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
}
}
但是,调用此方法时,数据仍然未刷新,这意味着我必须关闭应用程序并重新加载它以查看我的更改。我的代码中是否存在导致SQL数据保持不变的问题?有一个更好的方法吗?我还应该注意,我使用refreshCall
中完全相同的代码在表单初始化时加载数据,并且工作正常。
感谢任何帮助!
答案 0 :(得分:3)
似乎第二种形式是创建主窗体的新实例。永远不会显示新实例。您需要为refreshCall获取现有的主表单。
答案 1 :(得分:1)
当您打开第二个表单时,在主表单上,您可以使用以下代码。
// the ShowDialog will open your second form and then you use your DialogResult
// from the second form to tell your main form to refresh the data
yourSecondForm openSecondForm = new yourSecondForm.ShowDialog();
if(openSecondForm.DialogResult == DialogResult.OK)
{
refreshCall()
}
然后在你的finally块中的第二种形式:
finally
{
//Close the connection
if (conn.State != ConnectionState.Closed)
{
//Close the connection
}
//Close the window
DialogResult = DialogResult.OK;
}