我正在尝试编写一个将通过坐标输出的程序。我使用windows.h include和函数WriteConsoleOutputCharacter将字符打印到屏幕,但它忽略了SetConsoleTextAttribute设置的颜色。有任何想法如何让它以彩色输出?
输出到控制台的代码:
void Card::printFancy(COORD coord, bool top) const
{
paint();
LPDWORD written(0);
for (int row(0); row < CARD_WIDTH; ++row)
{
coord.Y += 1;
WriteConsoleOutputCharacter(Colorizer::getInstance().getCon(), _card[row], CARD_WIDTH, coord, written);
}
unpaint();
}
并且paint基本上使用适当的颜色调用Colorizer类中的绘制函数 Colorizer绘画功能(由paint()和unpain()调用:
void paint(uint color)
{
SetConsoleTextAttribute(_con, color);
}
_con
是句柄,通过_con = GetStdHandle(STD_OUTPUT_HANDLE);
答案 0 :(得分:1)
它是WriteConsoleOutputAttribute()的对应物。一个人写一个字符但不改变属性。另一个写入属性但不更改字符。
改为使用WriteConsole()。
答案 1 :(得分:0)
根据Hans Passant中https://stackoverflow.com/a/9275247/15485的建议,您可以将WriteConsoleOutputCharacter
与WriteConsoleOutputAttribute
匹配。
#include <windows.h>
#include <stdio.h>
void write_symbol_in_color(HANDLE h, SHORT x, SHORT y, const char* symbol, WORD color)
{
COORD here;
here.X = x;
here.Y = y;
WORD attribute = color;
DWORD written;
::WriteConsoleOutputAttribute(h, &attribute, 1, here, &written);
::WriteConsoleOutputCharacterA(h, symbol, 1, here, &written);
}
int main()
{
HANDLE hStdOut = ::GetStdHandle(STD_OUTPUT_HANDLE);
if (hStdOut == INVALID_HANDLE_VALUE)
{
printf("Invalid handle");
return 1;
}
write_symbol_in_color(hStdOut, 0, 0, "R", FOREGROUND_RED | FOREGROUND_INTENSITY);
write_symbol_in_color(hStdOut, 1, 0, "G", FOREGROUND_GREEN | FOREGROUND_INTENSITY);
write_symbol_in_color(hStdOut, 2, 0, "B", FOREGROUND_BLUE | FOREGROUND_INTENSITY);
write_symbol_in_color(hStdOut, 3, 0, "C", FOREGROUND_GREEN | FOREGROUND_BLUE | FOREGROUND_INTENSITY);
write_symbol_in_color(hStdOut, 4, 0, "M", FOREGROUND_RED | FOREGROUND_BLUE | FOREGROUND_INTENSITY);
write_symbol_in_color(hStdOut, 5, 0, "Y", FOREGROUND_RED | FOREGROUND_GREEN | FOREGROUND_INTENSITY);
return 0;
}