我发现很多关于舍入“下降”时间值的帖子(例如https://stackoverflow.com/a/6667041/468823),但我有另一个问题:我想要更高的分钟而不是更低的分钟,我该怎么办? / p>
我的代码:
SELECT
PA.ORE AS TOT_HOURS,
CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME) AS BEGIN_TIME,
CAST(dateadd(minute, datediff(minute, 0, (CAST(PA.ORA_INIZIO AS DATETIME))), 0) AS TIME) AS BEGIN_TIME_ROUNDED
FROM PRG_ATTIVITA PA INNER JOIN PRG_TIPI_ATTIVITA PTA ON PA.ID_TIPO_ATTIVITA = PTA.ID_TIPO_ATTIVITA
INNER JOIN PER_ANAGRAFICA PAN ON PA.ID_DIPENDENTE = PAN.ID_DIPENDENTE
WHERE PA.ID_PROGETTO = 1431 and pta.DESCR_TIPO_ATTIVITA like 'F-%remoto%' and ID_ATTIVITA = 41772
ORDER BY PA.DATA_ATTIVITA
我的结果如下:
TOT_HOURS BEGIN_TIME BEGIN_TIME_ROUNDED
1.50 15:59:59.9970000 15:59:00.0000000
我想要BEGIN_TIME_ROUNDED = 16:00:00.0000000
注意: 1.我必须转换我的数据{CAST(PA.ORA_INIZIO AS DATETIME)},因为在数据库中我有时间数据作为浮点值 2. BEGIN_TIME是转换后我的时间值的实际值
答案 0 :(得分:3)
刚过CAST到smalldatetime四舍五入到最接近的分钟
SELECT
CAST(CAST('15:59:59.9970000' AS time) AS smalldatetime),
CAST(CAST('15:59:30.0030000' AS time) AS smalldatetime),
CAST(CAST('15:59:30.0000000' AS time) AS smalldatetime),
CAST(CAST('15:59:29.9970000' AS time) AS smalldatetime),
CAST(CAST('15:59:00.0030000' AS time) AS smalldatetime)
DATEADD / DATEDIFF用于截断一些时间单位
编辑,误读问题
只需修改您当前的CAST
即可CAST(
DATEADD(minute,
DATEDIFF(minute,
0,
CAST(PA.ORA_INIZIO AS DATETIME)
) + 1,
0
)
AS TIME)
答案 1 :(得分:3)
SELECT DATEADD(MINUTE, CEILING(DATEDIFF(SECOND, 0, CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME)) / 60.0), DATEDIFF(DAY, 0, PA.ORA_INIZIO)) AS BEGIN_TIME_ROUNDED
答案 2 :(得分:1)
不知道SQL Server是否能够很好地回答,但如果没有人通过更实际的方式来实现这一点,那么你可以在将其向下舍入之前添加1分钟。如果您还需要正确处理整数输入值,请添加0.999分钟。
答案 3 :(得分:1)
declare @t time
set @t = '10:28:00.001'
select cast(dateadd(millisecond, 29999, @t) as smalldatetime)
答案 4 :(得分:0)
如果你想将DATETIME d舍入到最近的分钟,你可以这样做:
CONVERT(DATETIME, CONVERT(SMALLDATETIME,
DATEADD(minute, CASE WHEN d = CONVERT(SMALLDATETIME, d) THEN 0 ELSE 1 END,
d)))