Question

如何在mysql中组合这两个查询？

 select count(*) as entry_count from tbl_entries where user_id = x

和

select username, avatar from tbl_users where user_id = x

我想要一个结合了这两个查询结果的结果。请帮帮我们！

谢谢！

Answer 1

select username, 
       avatar,
       (select count(*) from tbl_entries where user_id = x) as entry_count
from tbl_users 
where user_id = x

Answer 2

select username,
       avatar,
       (select count(*) from tbl_entries where user_id = x) AS cnt
  from tbl_users
 where user_id = x

Answer 3

试试这个：

SELECT a.username,
        a.avatar,
        COUNT(*) as entry_count,
FROM tbl_Users a LEFT JOIN tbl_entries b ON
        a.user_ID = b.user_ID
WHERE a.user_ID = x
GROUP BY a.username

Answer 4

试试这个：

SELECT U.username, U.avatar, 
    count(*) AS entry_count 
FROM tbl_users AS U
LEFT JOIN tbl_entries AS E ON U.user_id = E.user_id
WHERE user_id = x
GROUP BY U.user_id;

Answer 5

SELECT用户名，化身，（从tbl_entries中选择count（*），其中user_id = U.user_id）AS cnt 来自tbl_users AS U. WHERE user_id = x

mysql用另一个select count选择count

5 个答案: