Question

我有以下xml我需要读取以下值：

<po-response xmlns="http://test.com<" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="rest/oms/export/v3/purchase-order.xsd">
  <!--Generated on Sellpo host [spapp402p.prod.ch4.s.com]-->
  <purchase-order>
    <customer-order-confirmation-number>123456</customer-order-confirmation-number>
    <customer-email>test@test.com</customer-email>
    <po-number>00001</po-number>
    <po-date>2012-02-12</po-date>
    <po-time>06:58:40</po-time>
    <po-number-with-date>12100000000</po-number-with-date>
    <unit>123</unit>
    <site>Test</site>
    <channel>VD</channel>
    <location-id>1234</location-id>
    <expected-ship-date>2012-02-13</expected-ship-date>
    <shipping-detail>
      <ship-to-name>JON DOE</ship-to-name>
      <address>123 SOMETHING STREET</address>
      <city>NEW NEW</city>
      <state>PS</state>
      <zipcode>BG121</zipcode>
      <phone>012030401</phone>
      <shipping-method>Ground</shipping-method>
    </shipping-detail>
  </purchase-order>
</po-response>

我正在尝试从shipping-detail元素中提取信息，但是没有任何内容被带回来？

                xmlDoc = XDocument.Parse(sr.ReadToEnd());

                var details = from detail in xmlDoc.Descendants("shipping-detail")
                                select new
                                {
                                    Name = detail.Element("ship-to-name").Value,
                                    Address = detail.Element("Address").Value,
                                    City = detail.Element("city").Value,
                                };


                foreach (var detail in details)
                {
                    Console.WriteLine("Ship to Name: " + detail.Name);
                    Console.WriteLine("Ship to Name: " + detail.Address);
                    Console.WriteLine("Ship to Name: " + detail.City);
                }

Answer 1

目前您的XML无效 - 假设您的名称空间声明与此xmlns="http://test.com"类似，您可以使用命名空间获取节点：

xmlDoc = XDocument.Parse(sr.ReadToEnd());
XNamespace ns = "http://test.com";
var details = from detail in xmlDoc.Descendants(ns + "shipping-detail")
                select new
                {
                    Name = detail.Element(ns + "ship-to-name").Value,
                    Address = detail.Element(ns + "address").Value,
                    City = detail.Element(ns + "city").Value,
                };

另请注意，节点名称区分大小写，因此它是"address"而不是"Address"。

Answer 2

您的查询摘要：

xmlDoc.Descendants("shipping-detail")

将查看Root节点。您没有任何名为“shipping-detail”的根节点。

尝试

xmlDoc.Root.Descendants("shipping-detail")

阅读XML没有带来任何结果

2 个答案: