我希望这个问题不会因为没有建设性而被关闭。我一直在敲我的头来解决这个问题但仍然无处可去。所以，这是我最后的希望：
问题基本上是关于生成ISO 8583-Rev 93消息的MAC字段
我有一些有效消息的转储，我正在尝试生成正确的MAC。
DES，Mode=CBC，IV = new byte[] {0, 0, 0, 0, 0, 0, 0, 0} new byte[] { 0x11, 0x11, 0x11, 0x11, 0x11, 0x11, 0x11, 0x11 } new byte[] { 49, 50, 48, 48, 70, 54, 51, 52, 56, 52, 48, 49, 56, 56, 69, 49, 49, 48, 48, 48, 48, 49, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 22, 54, 50, 56, 48, 50, 51, 49, 49, 49, 48, 48, 48, 48, 54, 52, 50, 51, 49, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 48, 49, 49, 54, 48, 56, 48, 56, 52, 53, 51, 57, 55, 57, 56, 54, 49, 50, 48, 49, 49, 54, 49, 49, 51, 56, 52, 53, 48, 48, 48, 48, 48, 49, 49, 54, 54, 49, 48, 53, 48, 48, 54, 49, 51, 49, 55, 67, 6, 54, 50, 56, 48, 50, 51, 6, 54, 50, 56, 48, 50, 51, 53, 49, 52, 50, 52, 49, 52, 51, 50, 53, 52, 51, 48, 57, 57, 57, 57, 52, 48, 50, 48, 48, 48, 48, 48, 57, 57, 57, 57, 52, 48, 50, 32, 32, 32, 7, 84, 101, 108, 66, 97, 110, 107, 0, 0, 51, 55, 54, 69, 55, 49, 67, 68, 69, 49, 68, 56, 54, 54, 51, 54, 0, 0 };
BF327C0CED48F26B值，该值进入消息的第128个字段。 这是我尝试过的（以及更多实现）：
var mac = Encrypt(dataToEncrypt);
// Convert to hex representation.
var hexMac = IsoUtils.ByteArrayToHex(mac);
// No BF327C0CED48F26B is in hexMac! something is probably wrong!
/// <summary>
/// Encrypts the input data. Tried many other ways with the same result.
/// </summary>
public byte[] Encrypt(byte[] input)
{
DESCryptoServiceProvider desProvider = new DESCryptoServiceProvider();
desProvider.Padding = PaddingMode.None;
desProvider.Mode = CipherMode.CBC;
ICryptoTransform cryptoTransform = desProvider.CreateEncryptor(this._key, this._iv);
MemoryStream encryptedStream = new MemoryStream();
CryptoStream cryptStream = new CryptoStream(encryptedStream, cryptoTransform, CryptoStreamMode.Write);
cryptStream.Write(input, 0, input.Length);
cryptStream.FlushFinalBlock();
encryptedStream.Position = 0;
byte[] result = new byte[encryptedStream.Length];
encryptedStream.Read(result, 0, (int)encryptedStream.Length);
cryptStream.Close();
return result;
}
/// <summary>
/// Gets the hex representation of the byte array. The length is 2xdata.Length
/// </summary>
public static string ByteArrayToHex(byte[] data)
{
string result = string.Empty;
foreach (byte ascii in data)
{
var n = (int)ascii;
result += n.ToString("X").PadLeft(2, '0');
}
return result;
}
简而言之，如何通过加密BF327C0CED48F26B变量来实现dataToEncrypt？
我真的很感激任何帮助。
更新：以下是可能有任何帮助的消息详情：
------------------------------------------------------------------------
Data For Encryption
------------------------------------------------------------------------
HEX NORMAL
31 32 30 30 46 36 33 34 38 34 30 31 38 38 45 31 1200F634840188E1
31 30 30 30 30 31 30 30 30 30 30 30 30 30 30 30 1000010000000000
30 30 30 30 16 36 32 38 30 32 33 31 31 31 30 30 000062802311100
30 30 36 34 32 33 31 30 30 30 30 30 30 30 30 30 0064231000000000
30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 0000000000000000
30 30 30 30 31 31 36 30 38 30 38 34 35 33 39 37 0000116080845397
39 38 36 31 32 30 31 31 36 31 31 33 38 34 35 30 9861201161138450
30 30 30 30 31 31 36 36 31 30 35 30 30 36 31 33 0000116610500613
31 37 43 60 36 32 38 30 32 33 60 36 32 38 30 32 17C62802362802
33 35 31 34 32 34 31 34 33 32 35 34 33 30 39 39 3514241432543099
39 39 34 30 32 30 30 30 30 30 39 39 39 39 34 30 9940200000999940
32 20 20 20 70 54 65 6C 42 61 6E 6B 00 00 33 37 2 TelBank 37
36 45 37 31 43 44 45 31 44 38 36 36 33 36 00 00 6E71CDE1D86636
------------------------------------------------------------------------
Message ready to be sent
------------------------------------------------------------------------
HEX NORMAL
30 32 32 34 31 32 30 30 46 36 33 34 38 34 30 31 02241200F6348401
38 38 45 31 31 30 30 30 30 31 30 30 30 30 30 30 88E1100001000000
30 30 30 30 30 30 30 31 16 36 32 38 30 32 33 31 000000016280231
31 31 30 30 30 30 36 34 32 33 31 30 30 30 30 30 1100006423100000
30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 0000000000000000
30 30 30 30 30 30 30 30 31 31 36 30 38 30 38 34 0000000011608084
35 33 39 37 39 38 36 31 32 30 31 31 36 31 31 33 5397986120116113
38 34 35 30 30 30 30 30 31 31 36 36 31 30 35 30 8450000011661050
30 36 31 33 31 37 43 60 36 32 38 30 32 33 60 36 061317C6280236
32 38 30 32 33 35 31 34 32 34 31 34 33 32 35 34 2802351424143254
33 30 39 39 39 39 34 30 32 30 30 30 30 30 39 39 3099994020000099
39 39 34 30 32 20 20 20 70 54 65 6C 42 61 6E 6B 99402 TelBank
00 00 33 37 36 45 37 31 43 44 45 31 44 38 36 36 376E71CDE1D866
33 36 00 00 42 46 33 32 37 43 30 43 45 44 34 38 36 BF327C0CED48
46 32 36 42 00 00 00 00 F26B
------------------------------------------------------------------------
Fields
------------------------------------------------------------------------
[LLVar n ..19 0016] 002 [6280231110000642]
[Fixed n 6 0006] 003 [310000]
[Fixed n 12 0012] 004 [000000000000]
[Fixed n 12 0012] 006 [000000000000]
[Fixed n 10 0010] 007 [0116080845]
[Fixed n 6 0006] 011 [397986]
[Fixed n 12 0012] 012 [120116113845]
[Fixed n 4 0004] 014 [0000]
[Fixed n 4 0004] 017 [0116]
[Fixed an 12 0012] 022 [61050061317C]
[LLVar n ..11 0006] 032 [628023]
[LLVar n ..11 0006] 033 [628023]
[Fixed an 12 0012] 037 [514241432543]
[Fixed an 8 0008] 041 [09999402]
[Fixed ans 15 0015] 042 [000009999402 ]
[LLVar ans ..40 0007] 043 [TelBank]
[LLLVar ans ..999 0000] 048 []
[Fixed an 16 0016] 052 [376E71CDE1D86636]
[LLLVar ans ..999 0000] 072 []
[Fixed an 16 0016] 128 [BF327C0CED48F26B]
更新2：
好吧，那些白痴忘记在他们的文件中提到，字段128应该填充0并且然后被发送加密。通过尝试和错误找到了这个！
答案 0 :(得分：3)
MAC只是CBC加密的最后8个字节。
您应该只计算部分消息的MAC。我不相信ISO 8583指定哪些部分，因此您需要查看您应该由银行提供的规范。
答案 1 :(得分：1)
CBC Mac，如果这是他们正在做的事情，通常是通过长度||来完成的消息在哪里||是串联。所以你只需要调用desEncrypt（length || message，key，cbcmode）或类似的东西