Question

我正在使用MS Access在ASP.net（C＃）中执行一个小应用程序。我有一个Gridview，我有一个“更新”命令。在运行期间，我在RowUpdating（）方法中放置了断点。一切正常，没有错误，参数在后面的代码中得到更新。但是在输出中，gridview没有更新，也没有在DB中。

这是代码：

protected void GridView1_RowUpdating(object sender, GridViewUpdateEventArgs e) 
{    
    string ID = GridView1.Rows[e.RowIndex].Cells[1].Text; 
    string CName= ((TextBox)GridView1.Rows[e.RowIndex].Cells[2].Controls[0]).Text; 
    string AName = ((TextBox)GridView1.Rows[e.RowIndex].Cells[3].Controls[0]).Text; 
    string APhone = ((TextBox)GridView1.Rows[e.RowIndex].Cells[4].Controls[0]).Text;
    string AEmail = ((TextBox)GridView1.Rows[e.RowIndex].Cells[5].Controls[0]).Text;
    string Note = ((TextBox)GridView1.Rows[e.RowIndex].Cells[6].Controls[0]).Text;

    UpdateRecord(ID, CName, AName, APhone, AEmail, Note); // GridView1.EditIndex = -1; BindGridView();
}

UpdateRecord（）方法：

更新方法运行良好，在使用断点运行期间，所有参数都获取更新的值，但它不会显示在gridview中，也不会在DB中更新

private void UpdateOrAddNewRecord(string ID, string CName, string AName, string APhone, string AEmail, string Note)    
{
    OleDbConnection connection = null;
    string conStr = @"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:\Documents and Settings\arjun.giridhar\Desktop\db1.mdb;Persist Security Info=False";

    string sqlStatement = "UPDATE Carriers" + " SET CarrierName = @CarrierName, AccountRepName = @AccountRepName, AccountRepContactPhone = @AccountRepContactPhone, AccountRepEmail= @AccountRepEmail, Notes=@Notes" + " WHERE CarrierID = @CarrierID";

    try
    {
        connection = new OleDbConnection(conStr);

        connection.Open();
        OleDbCommand cmd = new OleDbCommand(sqlStatement, connection);
       cmd.Parameters.AddWithValue("@CarrierID", ID);
        cmd.Parameters.AddWithValue("@CarrierName", CName);
        cmd.Parameters.AddWithValue("@AccountRepName", AName);
        cmd.Parameters.AddWithValue("@AccountRepContactPhone", APhone);
        cmd.Parameters.AddWithValue("@AccountRepEmail", AEmail);
        cmd.Parameters.AddWithValue("@Notes", Note);
        cmd.CommandType = CommandType.Text;
        cmd.ExecuteNonQuery();
    }
    catch (Exception ex)
    {
        string msg = "Update Error:";
        msg += ex.Message;
        throw new Exception(msg);

    }
    finally
    {
        connection.Close();
    }
}

BindGridView（）方法：

private void BindGridView()    
{
    DataTable dt = new DataTable();
    OleDbConnection connection = new OleDbConnection(conStr);
    try
    {
        connection.Open();
        string sqlStatement = "SELECT * FROM Carriers";
        OleDbCommand cmd = new OleDbCommand(sqlStatement, connection);
        OleDbDataAdapter sqlDa = new OleDbDataAdapter(cmd);
        sqlDa.Fill(dt);
        if (dt.Rows.Count > 0)
        {
            GridView1.DataSource = dt;
         GridView1.DataSourceID = string.Empty;
            GridView1.DataBind();
        }
    }
    catch (System.Data.SqlClient.SqlException ex)
    {
        string msg = "Fetch Error:";
        msg += ex.Message;
        throw new Exception(msg);
    }
    finally
    {
        connection.Close();
    }

}

请给我一个解决方案。

此致阿琼

Answer 1

我在这里找到了另一篇文章：Gridview not updating value说这是由于Page_Load中的网格绑定而没有检查回发引起的。我将Page_load更改为：

    protected void Page_Load(object sender, EventArgs e)
    {
        if (!Page.IsPostBack)
        {
            BindGridView();
        }
    }

那很有效。

Gridview更新错误

1 个答案: