Question

我有一些线程检查，我可以通过调用BeginInvoke(new Action<string,string>........来完成下面的工作，但我想知道你是否可以某种方式使用预定义的动作？

private Action<string, string> DoSomething();

private void MakeItHappen(string InputA, string InputB)
{
  if (this.InvokeRequired)
  {
    this.BeginInvoke(DoSomething(InputA, InputB));
  }
  else
  {
     Label.Text = "Done";
     MyOtherGUIItem.Visible = false;
  }

}

Answer 1

这是你的意思吗？

private Action<string, string> _DoSomething;

public void ConfigureToSecondThanFirstByExistingFunction()
{
    _DoSomething = MyMakeItLowerImplementation;
}

public void ConfigureToFirstThenSecondByLambda()
{
    _DoSomething = (a, b) => Console.WriteLine(a + b);
}

public void CallMe()
{
    ConfigureToSecondThanFirstByExistingFunction();
    //ConfigureToFirstThenSecondByLambda();

    _DoSomething("first", "second");
}

private void MyMakeItLowerImplementation(string a, string b)
{
    Console.WriteLine(b + a);
}

Answer 2

如果我理解正确你想要这样的东西吗？

private delegate void updateDelegate(string p1, string p2);
private updateDelegate DoSomething;

private void MakeItHappen(string InputA, string InputB)
{
    if (this.InvokeRequired)
    {
        this.BeginInvoke(DoSomething, InputA, InputB);
    }
    else
    {
        //Do stuff
    }
}

Answer 3

您必须将普通delegate传递给BeginInvoke。您可以使用变量捕获来包装您的参数，如下所示：

private void MakeItHappen(string InputA, string InputB)
{
    if (this.InvokeRequired)
    {
        this.BeginInvoke((Action)delegate () { 
            MakeItHappen(InputA, InputB); 
        });
    }
    else
    {
        // do stuff with InputA and InputB
    }
}

Answer 4

这样？：

private delegate void DoSomethingHandler(string A, string B);
private event DoSomethingHandler DoSomething;

public void Start()
{
   DoSomething = (a, b) => { /*doStuff*/ };
}

private void MakeItHappen(string InputA, string InputB)
{
  if (this.InvokeRequired)
  {
    this.BeginInvoke(DoSomething, InputA, InputB);
  }
  else
  {
    //Do stuff
  }    
}

你能在Control.BeginInvoke </t>中使用预定义的Action <t>吗？

4 个答案: