我一直在尝试从这个论坛和其他许多方面解决这个问题的许多不同方法。我似乎无法找到解决这个问题的方法或任何能给我直接答案的文档。
我想知道你是否可以帮我看一下。
由于
问题:
我有一个包含以下表格的数据库 participant_scores 联赛 轮
我目前能够显示单轮的分数,一次一轮...这正是我想要的。 但是我也希望显示每个参与者在所有轮次中获得的分数。 让我们说我们有2轮。我希望结果屏幕上的输出看起来像这样:
Currently viewing league 20, Round 1
of 2:
User Name | Score | Total Score
Tom | 10 | 200
James | 50 | 300
用户名 - 参与者的姓名 得分=本轮的得分 总得分=这个联赛的所有回合分数加在一起。
我的Mysql查询如下。为它的混乱道歉,我已经重写了大约100次,而这种当前的方式是完全可行的唯一方式。
# FIELDS
SELECT
participants.participant_id, # ID - used for functions
participants.participant_name, # NAME
participants.participant_gender, # Participant info
classes.class_name, # Class name
schools.school_name, # School name
participant_scores.participant_score, # Participant score
participant_scores.participant_score_id
# TABLES
FROM participant_scores, participants, classes, league_schools, schools, leagues, rounds
# filter leagues
WHERE leagues.league_id = 51
AND rounds.league_id = 51 # the current league we are viewing
AND rounds.round_id = 25 # the current round of the league we are viewing
# filter league schools
AND participant_scores.round_id = 25 # the current round of the league we are viewing
# filter schools allowed
AND league_schools.league_id = 51 # the current league we are viewing
# Filter schools
AND schools.school_id = league_schools.school_id
# Filter classes
AND classes.school_id = schools.school_id
AND classes.year_group_id = leagues.year_group_id
# Filter participants
AND participants.class_id = classes.class_id
# Filter participant_scores
AND participant_scores.participant_id = participants.participant_id
#Grouping
GROUP BY participants.participant_id
答案 0 :(得分:7)
这里你想要的是这种形式的子查询:
SELECT
name,
round,
score,
( select sum( score ) from scores sc where sc.userid = users.userid ) total
FROM users INNER JOIN scores on users.userid = scores.scoreid
将为您从初始查询返回的每一行计算作为列的子查询。
尝试将其添加到您的查询中:
SELECT
participants.participant_id,
participants.participant_name,
participants.participant_gender,
classes.class_name,
schools.school_name,
participant_scores.participant_score,
participant_scores.participant_score_id,
( SELECT sum(participant_score) FROM participant_scores tbl_scores2
WHERE tbl_scores2.participant_score_id = participants.participant_id ) total
FROM participant_scores, participants, classes,
league_schools, schools, leagues, rounds
WHERE
leagues.league_id = 51 AND
rounds.league_id = 51 AND
rounds.round_id = 25 AND
participant_scores.round_id = 25 AND
league_schools.league_id = 51 AND
schools.school_id = league_schools.school_id AND
classes.school_id = schools.school_id AND
classes.year_group_id = leagues.year_group_id AND
participants.class_id = classes.class_id AND
participant_scores.participant_id = participants.participant_id
GROUP BY
participants.participant_id
我有点担心包含多个联赛的子查询,但看起来单个参与者无论如何都只能属于一个联盟。您可能需要在子查询中包含一些内容来检查这一点。