Question

我是Java的新手并且正在尝试编写程序。这是代码。在count = 14时函数reduce，程序卡住了...... Plz让我知道我做错了什么..

public static class MerkleReducer extends MapReduceBase
implements Reducer<LongWritable, Text, LongWritable, Text> {

 static String[][] sarray = new String[5][14];
  static int count = 0;

 private void MerkleReducer() {
   for (int i=0;i<5;i++)
      for (int j=0; j<14;j++)
            sarray[i][j] += "";
 }

public void reduce(LongWritable key, Iterator<Text> values
  OutputCollector<LongWritable, Text> output, Reporter reporter) throws IOException {

    count++;
    Text hashval = new Text();
    while (values.hasNext()) {
           hashval = values.next();
    }
    sarray[0][(int)key.get()] += hashval.toString();
    if (count == 14) {
        for (int i=1; i<5; i++) { 
         for (int j=0; j<7; j = j++) { 
           int k = 2 * j;
           String hashv= new String();
           if ("".equals(sarray[i-1][k])) {
              break;
           }
           if ("".equals(sarray[i-1][k+1])) {
               sarray[i][j] = sarray[i-1][k];
               break;
           }
           hashv += sarray[i-1][k] + sarray[i-1][k+1];
           sarray[i][j] += hashv;

        }
       }
      output.collect(key, new Text(sarray[3][0]));

    } else {
        output.collect(key, new Text(hashval.toString()));
    }

} }

Answer 1

j = j++表示j永远不会更改，它将取j的当前值，增加j，然后将旧值重新分配回j

Answer 2

for (int j=0; j<7; j = j++) {

j = j++闻起来像无限。

java程序被卡住....我想我没有正确处理String对象

2 个答案: