我尝试使用mechanize(v0.2.5)来处理页面上的表单,该表单将禁用的图像作为表单元素之一。当我尝试选择表单时,mechanize会引发AttributeError: control 'test' is disabled
,其中test
是禁用控件的名称。例如,
br = mechanize.Browser(factory=mechanize.RobustFactory())
br.open("http://whatever...")
br.select_form(nr=0)
导致此堆栈跟踪:
br.select_form(nr=0)
File "build\bdist.win32\egg\mechanize\_mechanize.py", line 499, in select_form
File "build\bdist.win32\egg\mechanize\_html.py", line 544, in __getattr__
File "build\bdist.win32\egg\mechanize\_html.py", line 557, in forms
File "build\bdist.win32\egg\mechanize\_html.py", line 237, in forms
File "build\bdist.win32\egg\mechanize\_form.py", line 844, in ParseResponseEx
File "build\bdist.win32\egg\mechanize\_form.py", line 1017, in _ParseFileEx
File "build\bdist.win32\egg\mechanize\_form.py", line 2735, in new_control
File "build\bdist.win32\egg\mechanize\_form.py", line 2336, in __init__
File "build\bdist.win32\egg\mechanize\_form.py", line 1221, in __setattr__
AttributeError: control 'test' is disabled
检查机械化源代码,当有任何表单元素评估为mechanize.SubmitControl
并且没有预定义的value
属性时,看起来总是会引发此错误。例如,以下表单会引发相同的错误:
<form action="http://whatever" method="POST">
<input name="test" type="submit" disabled="disabled" />
</form>
我不确定这是否应该算作错误,但无论如何都有解决方法吗?例如,在调用br.select_form()
之前,有没有办法可以更改目标页面的HTML以启用已禁用的控件?
修改
我已经提交了一个机械化补丁修复了这个问题。
答案 0 :(得分:8)
可悲的是,这已经超过一年了,上游的机械化已经still not merged the pull request。
与此同时,您可以使用我编写的这个猴子补丁来解决这个问题,而无需手动安装补丁版本。希望在(if)0.2.6发布时解决此错误,因此补丁仅适用于0.2.5及更早版本。
def monkeypatch_mechanize():
"""Work-around for a mechanize 0.2.5 bug. See: https://github.com/jjlee/mechanize/pull/58"""
import mechanize
if mechanize.__version__ < (0, 2, 6):
from mechanize._form import SubmitControl, ScalarControl
def __init__(self, type, name, attrs, index=None):
ScalarControl.__init__(self, type, name, attrs, index)
# IE5 defaults SUBMIT value to "Submit Query"; Firebird 0.6 leaves it
# blank, Konqueror 3.1 defaults to "Submit". HTML spec. doesn't seem
# to define this.
if self.value is None:
if self.disabled:
self.disabled = False
self.value = ""
self.disabled = True
else:
self.value = ""
self.readonly = True
SubmitControl.__init__ = __init__
答案 1 :(得分:0)
这肯定是一个错误,向上游报告它,制作补丁,向上游提交它并在此期间使用补丁版本是处理它的相当正确的方法。 (感谢您选择这种方式。)
正如您所提到的,另一种方法是通过预处理源HTML来处理它(如果您匆忙,或者由于某些原因不能/不想使用修补版本,这可能很有用,但请注意该变通办法对社区没有帮助)。对于后处理,可以使用任何合适的方法 - 从str.replace()到使用BeautifulSoup或lxml的DOM级处理。