为什么这两个查询会返回不同的计数？

时间：2012-02-12 05:08:04

标签： sql sql-server sql-server-2008

此查询为[Specimen ID]

返回125000总计 
; with cte (rejected) as 
(

select distinct([specimen id])
from QuickLabDump
where  DATEPART(mm, [DATE entered]) = 01
and DATEPART(yyyy, [DATE entered]) = 2012
and QuickLabDump.Outcome='REJECTED'

)


    select [Specimen ID],max([Order Count]) from QuickLabDump
    left outer join cte
    on QuickLabDump.[Specimen ID]=cte.rejected
    where DATEPART(mm, [DATE entered]) = 01
    and DATEPART(yyyy, [DATE entered]) = 2012
    and cte.rejected is  null
    group by [Specimen ID]
    order by 2 desc

如果我在这里对Specimen ID做同样的计数，我会得到127000左右：

; with cte (rejected) as 
(

select distinct([specimen id])
from QuickLabDump
where  DATEPART(mm, [DATE entered]) = 01
and DATEPART(yyyy, [DATE entered]) = 2012
and QuickLabDump.Outcome='REJECTED'

)

select 
    [Full Date]=CONVERT(VARCHAR(8), [DATE entered], 1),
    [Year Entered]=DATEPART(yy, [DATE entered]) ,  
    [Month Entered]=LEFT(DATENAME(MONTH, [DATE entered]), 3),
    [Day Entered]=DATEPART(dd, [DATE entered]),
    [DOW]=
       case when DATEPART(WEEKDAY, [DATE entered])=1 THEN 'Sun'
       when DATEPART(WEEKDAY, [DATE entered])=2 THEN 'Mon'
       when DATEPART(WEEKDAY, [DATE entered])=3 THEN 'Tus'
       when DATEPART(WEEKDAY, [DATE entered])=4 THEN 'Wed'
       when DATEPART(WEEKDAY, [DATE entered])=5 THEN 'Thu'
       when DATEPART(WEEKDAY, [DATE entered])=6 THEN 'Fri'
       when DATEPART(WEEKDAY, [DATE entered])=7 THEN 'Sat'
       end,
    [Week Ending]=CONVERT(VARCHAR(8),
        DATEADD (D, -1 * DatePart (dw,[date entered]) + 6, [date entered]), 1),
    [CountAccns]=count(a.[specimen id]),
    [Sales Rep]=c.salesrep,
    [MLNPI]=c.npi,
    [IMSNPI]=e.npib,
    [IMS Specialty Primary Code]=e.SpecialtyPrimaryCodeb,
    [IMS Specialty Secondary Code]=e.SpecialtySecondaryCodeb,
    [IMS Specialty Tertiary Code]=e.SpecialtyTertiaryCodeb,
    [IMS Professional ID 1]=e.ProfessionalID1b,    
    [Physician]=[Requesting Physician],
    [Practice Code]=a.[practice code],
    [MLIS Code]=b.[mlis practice id],    
    [practice name],
    [Date Established]=c.dateestablished , 
    [Address]=c.practiceaddress1, 
    [Address2]=c.practiceaddress2,
    [City]=c.practicecity,
    [State]=c.practicestate,
    [Status]=b.[Active Inactive],
    [order count]=a.[order count]
from 
    quicklabdump a
    left outer join qlmlismapping b on (b.[practice code] = a.[practice code])
    left outer join PracticeandPhysician c on 
        a.[Requesting Physician]=c.doctorfirstname+' '+c.DOCTORLASTNAME 
        and a.[practice code]=c.practicecode
    left outer join IMSData e on c.NPI=e.npib
    left outer join cte
        on a.[Specimen ID]=cte.rejected

where    
     DATEPART(mm, [DATE entered]) = 01
    and DATEPART(yyyy, [DATE entered]) = 2012
    and cte.rejected is null

group by 
    a.[DATE entered],
    c.salesrep,
    c.npi,
    e.npib,
    e.SpecialtyPrimaryCodeb,
    e.SpecialtySecondaryCodeb,
    e.SpecialtyTertiaryCodeb,
    e.ProfessionalID1b,
    a.[Requesting Physician],
    a.[practice code],
    b.[mlis practice id],
    [practice name],
    c.dateestablished , 
    c.practiceaddress1, 
    c.practiceaddress2,
    c.practicecity,
    c.practicestate,
    b.[Active Inactive],
    a.[order count]
 having a.[order count]=max([order count])
    order by  [Practice Code] desc,Physician desc

为什么与伯爵有如此巨大的差异？你不认为它会完全相同，因为两个查询都应该返回相同的Specimen IDs总量吗？

我做错了什么？

3 个答案:

答案 0 :(得分：1)

马上我可以看到几个可能导致两个查询之间记录计数不同的因素：

  1. 在您的第一个查询中，您只是在第二个查询中按SpecimenID进行分组，而您正在按更多属性进行分组。
  2. 您的第二个查询包含一些额外的连接，这些连接很容易导致不同的结果计数
  3. 您的第二个查询包含Having谓词，第一个查询不是

答案 1 :(得分：1)

[标本ID]可以为空吗？如果是这样，我会在两个查询中尝试以下内容：

  1. Set ansi_nulls on
  2. 向两个查询中的cte添加AND [specimen id] IS NOT NULL
  3. 在第一个查询中，将QuickLabDump别名为a
  4. 删除left outer join cte...（两个查询）
  5. 删除and cte.rejected is null（两个查询）
  6. 将and not exists(select 1 from cte where [specimen id]=a.[specimen id])添加到两个主要查询中的where子句。

    7. 更新后的代码

    -- First Query  
set ansi_nulls on

; with cte (rejected) as  
(  
    select distinct([specimen id])  
    from QuickLabDump  
    where  DATEPART(mm, [DATE entered]) = 01  
    and DATEPART(yyyy, [DATE entered]) = 2012  
    and QuickLabDump.Outcome='REJECTED'  
    and [specimen id] is not null  
)  
select [Specimen ID],max([Order Count])  
from QuickLabDump a  
where DATEPART(mm, [DATE entered]) = 01  
and DATEPART(yyyy, [DATE entered]) = 2012  
and not exists(select 1 from cte where rejected=a.[Specimen ID])  
group by [Specimen ID]  
order by 2 desc  
go  

-- Second Query  
set ansi_nulls on  
; with cte (rejected) as   
(  
    select distinct([specimen id])  
    from QuickLabDump  
    where  DATEPART(mm, [DATE entered]) = 01  
    and DATEPART(yyyy, [DATE entered]) = 2012  
    and QuickLabDump.Outcome='REJECTED'  
    and [specimen id] is not null  
)  
select   
    [Full Date]=CONVERT(VARCHAR(8), [DATE entered], 1),  
    [Year Entered]=DATEPART(yy, [DATE entered]) ,  
    [Month Entered]=LEFT(DATENAME(MONTH, [DATE entered]), 3),  
    [Day Entered]=DATEPART(dd, [DATE entered]),  
    [DOW]=  
       case when DATEPART(WEEKDAY, [DATE entered])=1 THEN 'Sun'  
       when DATEPART(WEEKDAY, [DATE entered])=2 THEN 'Mon'  
       when DATEPART(WEEKDAY, [DATE entered])=3 THEN 'Tus'  
       when DATEPART(WEEKDAY, [DATE entered])=4 THEN 'Wed'  
       when DATEPART(WEEKDAY, [DATE entered])=5 THEN 'Thu'  
       when DATEPART(WEEKDAY, [DATE entered])=6 THEN 'Fri'  
       when DATEPART(WEEKDAY, [DATE entered])=7 THEN 'Sat'  
       end,  
    [Week Ending]=CONVERT(VARCHAR(8),  
        DATEADD (D, -1 * DatePart (dw,[date entered]) + 6, [date entered]), 1),  
    [CountAccns]=count(a.[specimen id]),  
    [Sales Rep]=c.salesrep,  
    [MLNPI]=c.npi,  
    [IMSNPI]=e.npib,  
    [IMS Specialty Primary Code]=e.SpecialtyPrimaryCodeb,  
    [IMS Specialty Secondary Code]=e.SpecialtySecondaryCodeb,  
    [IMS Specialty Tertiary Code]=e.SpecialtyTertiaryCodeb,  
    [IMS Professional ID 1]=e.ProfessionalID1b,      
    [Physician]=[Requesting Physician],  
    [Practice Code]=a.[practice code],  
    [MLIS Code]=b.[mlis practice id],      
    [practice name],  
    [Date Established]=c.dateestablished ,   
    [Address]=c.practiceaddress1,   
    [Address2]=c.practiceaddress2,  
    [City]=c.practicecity,  
    [State]=c.practicestate,  
    [Status]=b.[Active Inactive],  
    [order count]=a.[order count]  
from   
    quicklabdump a  
    left outer join qlmlismapping b on (b.[practice code] = a.[practice code])  
    left outer join PracticeandPhysician c on   
        a.[Requesting Physician]=c.doctorfirstname+' '+c.DOCTORLASTNAME   
        and a.[practice code]=c.practicecode  
    left outer join IMSData e on c.NPI=e.npib  
where    
     DATEPART(mm, [DATE entered]) = 01  
    and DATEPART(yyyy, [DATE entered]) = 2012  
    and cte.rejected is null  
    and not exists(select 1 from cte where rejected=a.[Specimen ID])  
group by   
    a.[DATE entered],  
    c.salesrep,  
    c.npi,  
    e.npib,  
    e.SpecialtyPrimaryCodeb,  
    e.SpecialtySecondaryCodeb,  
    e.SpecialtyTertiaryCodeb,  
    e.ProfessionalID1b,  
    a.[Requesting Physician],  
    a.[practice code],  
    b.[mlis practice id],  
    [practice name],  
    c.dateestablished ,  
    c.practiceaddress1,  
    c.practiceaddress2,  
    c.practicecity,  
    c.practicestate,  
    b.[Active Inactive],  
    a.[order count]  
 having a.[order count]=max([order count])  
    order by  [Practice Code] desc,Physician desc  
go

答案 2 :(得分：0)

我找到了罪魁祸首！

在第二个查询中，我正在进行[CountAccns]=count(a.[specimen id]),

实际上这应该是：

[CountAccns]=count(distinct(a.[specimen id])),

现在排好了两个计数!!

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