Question

我有一个JSF + Spring的应用程序。我正在使用spring security并且我正常工作。但是当我尝试在没有身份验证的情况下访问安全页面时，而不是将我重定向到被拒绝的页面，我只显示403 Forbidden页面。我不知道applicationContext或web.xml上是否有任何缺失，这是我的代码：

applicationContext的一部分：

<sec:http access-denied-page="/denied.xhtml"  auto-config="true" use-expressions="false" >
    <sec:form-login login-page="/login.xhtml" default-target-url="/"   authentication-failure-url="/denied.xhtml"
    login-processing-url="/static/j_spring_security_check"
    />
    <sec:intercept-url pattern="/PANEL/**"  access="ROLE_GENERALT"></sec:intercept-url>
    <sec:logout invalidate-session="true" logout-url="/index.xhtml"/>
    </sec:http>

<sec:global-method-security secured-annotations="enabled" jsr250-annotations="enabled"></sec:global-method-security>

和web.xml：

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>classpath:/appContext.xml
        </param-value>
    </context-param>
    <filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>

</filter>

<filter-mapping>
  <filter-name>springSecurityFilterChain</filter-name>
  <url-pattern>/*</url-pattern>
  <dispatcher>FORWARD</dispatcher>
  <dispatcher>REQUEST</dispatcher>
</filter-mapping>

Answer 1

您需要为发生AccessDeniedException时ExceptionTranslationFilter使用的accessDeniedHandler设置errorpage属性

请参阅此信息以获取信息link

<bean id="exceptionTranslationFilter" class="org.springframework.security.web.access.ExceptionTranslationFilter">
  <property name="authenticationEntryPoint" ref="authenticationEntryPoint"/>
  <property name="accessDeniedHandler" ref="accessDeniedHandler"/>
</bean>

<bean id="accessDeniedHandler" class="org.springframework.security.web.access.AccessDeniedHandlerImpl">
  <property name="errorPage" value="/denied.xhtml"/>
</bean>

或者，您可以将其添加到您的web.xml

<error-page>
  <error-code>403</error-code>
  <location>/pages/denied.xhtml</location>
</error-page>

如何使用spring security重定向到access-denied-page

1 个答案: