我需要对一个byte []进行base64编码,将其发送到http服务器,然后再读取一个编码的byte []。但是,j2me中没有Base64编码器/解码器。
我很感激这段代码!
br,perza
答案 0 :(得分:11)
我使用这个类:
public class Base64 {
static byte[] encodeData;
static String charSet =
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
static {
encodeData = new byte[64];
for (int i = 0; i<64; i++) {
byte c = (byte) charSet.charAt(i);
encodeData[i] = c;
}
}
private Base64() {}
/**
* base-64 encode a string
* @param s The ascii string to encode
* @returns The base64 encoded result
*/
public static String
encode(String s) {
return encode(s.getBytes());
}
/**
* base-64 encode a byte array
* @param src The byte array to encode
* @returns The base64 encoded result
*/
public static String
encode(byte[] src) {
return encode(src, 0, src.length);
}
/**
* base-64 encode a byte array
* @param src The byte array to encode
* @param start The starting index
* @param len The number of bytes
* @returns The base64 encoded result
*/
public static String
encode(byte[] src, int start, int length) {
byte[] dst = new byte[(length+2)/3 * 4 + length/72];
int x = 0;
int dstIndex = 0;
int state = 0; // which char in pattern
int old = 0; // previous byte
int len = 0; // length decoded so far
int max = length + start;
for (int srcIndex = start; srcIndex<max; srcIndex++) {
x = src[srcIndex];
switch (++state) {
case 1:
dst[dstIndex++] = encodeData[(x>>2) & 0x3f];
break;
case 2:
dst[dstIndex++] = encodeData[((old<<4)&0x30)
| ((x>>4)&0xf)];
break;
case 3:
dst[dstIndex++] = encodeData[((old<<2)&0x3C)
| ((x>>6)&0x3)];
dst[dstIndex++] = encodeData[x&0x3F];
state = 0;
break;
}
old = x;
if (++len >= 72) {
dst[dstIndex++] = (byte) '\n';
len = 0;
}
}
/*
* now clean up the end bytes
*/
switch (state) {
case 1: dst[dstIndex++] = encodeData[(old<<4) & 0x30];
dst[dstIndex++] = (byte) '=';
dst[dstIndex++] = (byte) '=';
break;
case 2: dst[dstIndex++] = encodeData[(old<<2) & 0x3c];
dst[dstIndex++] = (byte) '=';
break;
}
return new String(dst);
}
/**
* A Base64 decoder. This implementation is slow, and
* doesn't handle wrapped lines.
* The output is undefined if there are errors in the input.
* @param s a Base64 encoded string
* @returns The byte array eith the decoded result
*/
public static byte[]
decode(String s) {
int end = 0; // end state
if (s.endsWith("=")) {
end++;
}
if (s.endsWith("==")) {
end++;
}
int len = (s.length() + 3)/4 * 3 - end;
byte[] result = new byte[len];
int dst = 0;
try {
for(int src = 0; src< s.length(); src++) {
int code = charSet.indexOf(s.charAt(src));
if (code == -1) {
break;
}
switch (src%4) {
case 0:
result[dst] = (byte) (code<<2);
break;
case 1:
result[dst++] |= (byte) ((code>>4) & 0x3);
result[dst] = (byte) (code<<4);
break;
case 2:
result[dst++] |= (byte) ((code>>2) & 0xf);
result[dst] = (byte) (code<<6);
break;
case 3:
result[dst++] |= (byte) (code & 0x3f);
break;
}
}
} catch (ArrayIndexOutOfBoundsException e) {}
return result;
}
/**
* Test the decoder and encoder.
* Call as <code>Base64 [string]</code>.
*/
public static void
main(String[] args) {
System.out.println("encode: " + args[0] + " -> ("
+ encode(args[0]) + ")");
System.out.println("decode: " + args[0] + " -> ("
+ new String(decode(args[0])) + ")");
}
}
您可以使用编码和解码方法。