在SQL代码中而不是在cfoutput中

Question

我有一个城市的sql-server代码作为行和月作为列，有几个月的总和，但city_id没有总和，我的意思是我必须计算所有城市里面的总和输出，并按city_id分组，无论如何这里是sql代码：

SELECT 
    SC.CITY_ID,SC.CITY_NAME, DATEPART(MM,I.INVOICE_DATE) AS INVOICE_MONTH,
    JAN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=1 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    FEB=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=2 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    MAR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=3 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    APR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=4 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    MAY=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=5 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    JUN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=6 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    JUL=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=7 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    AUG=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=8 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    SEP=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=9 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    OCT=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=10 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    NOV=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=11 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
    DEC=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=12 THEN COALESCE(NETTOTAL,0) ELSE 0 END)
FROM 
    SETUP_CITY SC
    LEFT OUTER JOIN COMPANY C ON C.CITY = SC.CITY_ID
    LEFT OUTER JOIN #DSN2_ALIAS#.INVOICE I ON I.COMPANY_ID = C.COMPANY_ID AND I.INVOICE_CAT IN (50,52,53,531,532,56,58,561,54,55,51,63,48) AND I.PURCHASE_SALES = 1
WHERE SC.COUNTRY_ID=1
GROUP BY SC.CITY_ID,SC.CITY_NAME,I.INVOICE_DATE
ORDER BY SC.CITY_ID,SC.CITY_NAME,I.INVOICE_DATE

并输出：

<cfoutput query="get_top_sales_TOTAL" group="CITY_ID">

如果我没有按city_id定义组，则会显示一个城市的多行。如何在sql代码中对值（总结）进行分组？这样我就不必在cfoutput中使用group语句了吗？

以下是截图，使其更加清晰，这里是定义为group="city_id"

的屏幕截图

如果我没有定义group="city_id"

Answer 1

马克对invoice_month是正确的，没有必要这样做。你的“正确”sql应该是

SELECT 
        SC.CITY_ID,SC.CITY_NAME,
        TOTAL=SUM(COALESCE(NETTOTAL,0)),
        JAN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=1 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        FEB=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=2 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        MAR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=3 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        APR=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=4 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        MAY=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=5 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        JUN=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=6 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        JUL=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=7 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        AUG=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=8 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        SEP=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=9 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        OCT=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=10 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        NOV=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=11 THEN COALESCE(NETTOTAL,0) ELSE 0 END),
        DEC=SUM(CASE WHEN DATEPART(MM,I.INVOICE_DATE)=12 THEN COALESCE(NETTOTAL,0) ELSE 0 END)
FROM 
        SETUP_CITY SC
            LEFT OUTER JOIN COMPANY C ON C.CITY = SC.CITY_ID
            LEFT OUTER JOIN #DSN2_ALIAS#.INVOICE I ON I.COMPANY_ID = C.COMPANY_ID 
                    AND I.INVOICE_CAT IN (50,52,53,531,532,56,58,561,54,55,51,63,48) 
                    AND I.PURCHASE_SALES = 1
WHERE  SC.COUNTRY_ID=1
GROUP BY SC.CITY_ID, SC.CITY_NAME
ORDER BY SC.CITY_ID,SC.CITY_NAME

Answer 2

您的问题是，group by和order by中的“invoice_date”将产生多行。试试这个：

GROUP BY SC.CITY_ID, SC.CITY_NAME, DATEPART(MM,I.INVOICE_DATE)
ORDER BY SC.CITY_ID, SC.CITY_NAME,  INVOICE_MONTH

无法尝试，所以我无法调试它 - 但基本上你的GROUP不能在其中包含扩展行的唯一性的单个项目（作为“发票日期”可能会这样做）。祝好运！