Java JApplet将不再显示在任何浏览器中

时间:2012-02-11 05:01:07

标签: java swing user-interface applet japplet

Applet曾经工作过,但现在却不行。我对GUI的Applet不太熟悉。 这是GUI代码:

import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.util.*;
import java.io.*;

public class StockGUI extends JApplet implements ActionListener
{
private final String sPASS = "abc123";
//Stock oStock = new Stock();
//StockInput oStockInput = new StockInput();

//////////////////////////////////////////////////////////

JPanel jPanel;
JPasswordField jPass;
JButton jBEnter, jBYes, jBNo;
JTextArea jTAInput, jTACurrent;
JTextField jTxtField;
JLabel jLEnterP, jLQue, jLCurrent;
JScrollPane jScroll;




public void init()
{
    getContentPane().setLayout(null);
    jPanel = new JPanel();  jPanel.setSize(500,1500);

    ////////////////////////////////////////////////

    jPass = new JPasswordField(20);
    jPass.setActionCommand(sPASS);
    jLEnterP = new JLabel("Enter Password:");
    jPanel.add(jLEnterP);
    jPanel.add(jPass);

    jPass.addActionListener(new ActionListener()
    {
        public void actionPerformed(ActionEvent e)
        {
            String cmd = e.getActionCommand();
            if(cmd.equals(sPASS))
            {
                char[] cAry = jPass.getPassword();
                if(isPassword(cAry))
                {
                    doPass();
                }
            }
        }
    });

    getContentPane().add(jPanel, BorderLayout.CENTER);

}

public void actionPerformed(ActionEvent e)
{
    String cmd = e.getActionCommand();


    if(cmd.equals("Yes"))
    {

        doInput();

    }
    if(cmd.equals("No") || cmd.equals("Done"))
    {
        doMain();
    }

}

public void doPass()
{
        jPanel.removeAll();
        jLQue = new JLabel("Do you need to input more data?");
        jBYes = new JButton("Yes");

        jBYes.addActionListener(new ActionListener()
        {
            public void actionPerformed(ActionEvent e)
            {
                doInput();
            }
        });

        jBNo = new JButton("No");

        jBNo.addActionListener(new ActionListener()
        {
            public void actionPerformed(ActionEvent e)
            {
                doMain();
            }
        });

        jPanel.add(jLQue);
        jPanel.add(jBYes);
        jPanel.add(jBNo);
        refresh();

}

public void doInput()
{
    jPanel.removeAll();
    jLQue = new JLabel("Enter Data:");
    jTAInput = new JTextArea(25,50);
    jLCurrent = new JLabel("Current Data");
    jTACurrent = new JTextArea(25, 25);
        jTACurrent.setEditable(false);
        //jTACurrent.setText(oStockInput.getList());
    jScroll = new JScrollPane(jTACurrent);
    jPanel.add(jLQue);
    jPanel.add(jTAInput);
    refresh();
}

public void doMain()
{

    jPanel.removeAll();
    jPanel.add(new JLabel("HELLO WORKD!!"));
    refresh();

}

public void refresh()
{
    jPanel.repaint();
    jPanel.revalidate();
    super.validate();
    super.repaint();
}

public boolean isPassword(char[] cAry)
{

    return Arrays.equals(cAry, sPASS.toCharArray());

}

HTML代码:

//  <html>
//<body>
//<p align=center>
//<applet code="StockGUI.class" width=500 height=1500>
//  </applet>
//</p>
//</body>
//</html>

我在编译时没有错误。我正在尝试为ActionListeners使用匿名类,但这是我第一次使用它们。当我启动Chrome时,所有显示的都是白色背景。任何帮助都会很好。感谢。

2 个答案:

答案 0 :(得分:4)

我通常使用appletviewer来调试applet。将以下行添加到程序顶部并重新编译:

//<applet code="StockGUI.class" width="500" height="300"></applet>

然后,您可以使用以下命令从命令行测试applet:

appletviewer StockGUI.java

您可以添加调试语句以查看发生的情况。我这样做时会看到密码提示。

答案 1 :(得分:2)

检查Java控制台。它可能会导致失败。